The function is given by: f(x)=(x−2)2−9At what values of x does the graph of the function intersect the x-axis?Choose 1 answer:(A) x=−5,x=−1(B) x=5,x=1(C) x=−5,x=1(D) x=5,x=−1 Get tutor help
Sebuah satelit bisa gagal terbang karena faktor kesalahan mesin atau komputer. Untuk sebuah misi, diketahui bahwa probabilitas kesalahan mesin adalah 0,008, probabilitas kesalahan komputer adalah 0,001. Saat terjadi kesalahan mesin, probabilitas satelit gagal adalah 0,98 Saat terjadi probabilitas satelit gagal adalah 0,4 Saat terjadi kesalahan komponen lain, probabilitas satelit gagal o. a. Tentukan probabilitas satelit gagal terbang. b. Tentukan probabilitas satelit gagal terbang dan itu disebabkan karena kesalahan mesin. Get tutor helpSokMATH2250S24PS5.p...RaneyLinear AlgebraSpring 2024Problem Set 51. Show that x=⎣⎡−211⎦⎤ is an eigenvector of A=⎣⎡011112−110⎦⎤ and find the corresponding eigenvalue.2. Show that λ=i=−1 is an eigenvalue of A=[01−10], and find a corresponding eigenvector.3. Let A=[2640]. Find the eigenvalues of A and bases for the corresponding eigenspaces.4. Let A be an idempotent matrix (that is, A2=A ). Show that λ=0 and λ=1 are the only possible eigenvalues of A.5. Let A=⎣⎡011112−110⎦⎤1 be the linear transformation defined byT(p(x))=xp′(x)(a) Which, if any, of the polynomialsp1(x)=1,p2(x)=x,p3(x)=x2are in A=⎣⎡011112−110⎦⎤2 ?(b) Which, if any, of the polynomialsp1(x)=1,p2(x)=x,p3(x)=x2are in A=⎣⎡011112−110⎦⎤3 ?6. Find the dimension of the vector space A=⎣⎡011112−110⎦⎤4 and give a basis for A=⎣⎡011112−110⎦⎤5.7. Define a linear transformation A=⎣⎡011112−110⎦⎤6 byT(A)=AB−BAwhere A=⎣⎡011112−110⎦⎤7. Find a basis for A=⎣⎡011112−110⎦⎤2.(D)DashboardCalendarA=⎣⎡011112−110⎦⎤9To-doNotificationsλ=i=−10Inbox Get tutor help1. (6pts) Graph and label the Preimage and the image of A(−2,1),B(1,−1), and C(−3,3) after the dilation of scale factor 2 with the center of dilation being the origin.y-axis\begin{tabular}{|c|c|c|c|c|c|c|c|c|c|c|c|}\hline & & & & & 6↑ & & & & & & \\\hline & & & & & 5 & & & & & & \\\hline & & & & & 4 & & & & & & \\\hline & & & & & 3 & & & & & & \\\hline & & & & & 2 & & & & & & \\\hline & & & & & 1 & & & & & & \\\hline−6 & −5 & −4 & −3 & −2 & −1 & 1 & 2 & 3 & 4 & 5 & 6 \\\hline & & & & & −2 & & & & & & \\\hline & & & & & −3 & & & & & & \\\hline & & & & & −4 & & & & & & \\\hline & & & & & −5 & & & & & & \\\hline & & & & & −6 & & & & & & \\\hline\end{tabular} Get tutor help
