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Find the product.

-(1)/(3)*[[3,-6],[-3,9]]=

Find the product.\newline13[3639]= -\frac{1}{3} \cdot\left[\begin{array}{cc} 3 & -6 \\ -3 & 9 \end{array}\right]=

Full solution

Q. Find the product.\newline13[3639]= -\frac{1}{3} \cdot\left[\begin{array}{cc} 3 & -6 \\ -3 & 9 \end{array}\right]=
  1. Understand Operation: Understand the operation to be performed.\newlineWe need to multiply each element of the matrix \left[\begin{array}{cc}\(\newline3 & -6 (\newline\)-3 & 9\newline\end{array}\right]\) by the scalar 13-\frac{1}{3}.
  2. Multiply First Element: Multiply the first element of the matrix by 13-\frac{1}{3}. 13×3=1-\frac{1}{3} \times 3 = -1
  3. Multiply Second Element: Multiply the second element of the matrix by 13-\frac{1}{3}.13×6=2 -\frac{1}{3} \times -6 = 2
  4. Multiply Third Element: Multiply the third element of the matrix by 13-\frac{1}{3}. \newline13×3=1-\frac{1}{3} \times -3 = 1
  5. Multiply Fourth Element: Multiply the fourth element of the matrix by 13-\frac{1}{3}. 13×9=3-\frac{1}{3} \times 9 = -3
  6. Combine Results: Combine the results to form the new matrix. The resulting matrix after multiplying by 13-\frac{1}{3} is [12 13]\left[\begin{array}{cc} -1 & 2 \ 1 & -3 \end{array}\right].