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{:[f(x)=14-0.5 x],[f(30)=]:}

$\begin{array}{l}f(x)=14-0.5 x \\ f(30)=\square\end{array}$

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Multiply two decimals: where does the decimal point go?

Full solution

Q.

\begin{array}{l}f(x)=14-0.5 x \\ f(30)=\square\end{array}

Substitute $x$ with $30$ : To find the value of $f(30)$ , we need to substitute $x$ with $30$ in the function $f(x) = 14 - 0.5x$ .
Multiply $0.5$ by $30$ : Now, let's substitute $x$ with $30$ : $f(30) = 14 - 0.5 \times 30$ .
Subtract the result from $14$ : Next, we multiply $0$ . $5$ by $30$ : $0$ . $5$ \times $30$ = $15$ .
Calculate the final result: Then, we subtract the result from $14$ : $14 - 15$ .
Calculate the final result: Then, we subtract the result from $14$ : $14 - 15$ . The calculation gives us: $14 - 15 = -1$ .
Calculate the final result: Then, we subtract the result from $14$ : $14 - 15$ . The calculation gives us: $14 - 15 = -1$ . Therefore, the value of $f(30)$ is $-1$ .

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