Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Grade 6
Multiply two decimals: where does the decimal point go?
2.6
−
0.029
log
[
0.1
]
2.6 -0.029\log_{[0.1]}
2.6
−
0.029
lo
g
[
0.1
]
Get tutor help
3.75
−
81
3.75-81
3.75
−
81
Get tutor help
21.5
−
32
21.5 - 32
21.5
−
32
Get tutor help
log
1.25
0.8
=
−
t
\log _{1.25} 0.8=-t
lo
g
1.25
0.8
=
−
t
Get tutor help
4.82
4.82
4.82
,
11.
1.2
11.\quad 1.2
11.
1.2
Get tutor help
Which equation is true?
\newline
0.35
÷
0.7
=
5
0.35 \div 0.7=5
0.35
÷
0.7
=
5
\newline
0.1
÷
0.35
=
0.35
0.1 \div 0.35=0.35
0.1
÷
0.35
=
0.35
\newline
0.7
÷
0.35
=
2
0.7 \div 0.35=2
0.7
÷
0.35
=
2
\newline
0.5
÷
0.35
=
7
0.5 \div 0.35=7
0.5
÷
0.35
=
7
Get tutor help
Solve for
t
t
t
:
\newline
3
t
=
−
8.16
t
=
□
\begin{array}{l} 3 t=-8.16 \\ t=\square \end{array}
3
t
=
−
8.16
t
=
□
Get tutor help
Solve for
f
f
f
:
\newline
f
−
3.2
=
0.01
f
=
□
\begin{array}{l} \frac{f}{-3.2}=0.01 \\ f=\square \end{array}
−
3.2
f
=
0.01
f
=
□
Get tutor help
Solve for
x
x
x
:
\newline
x
−
4
=
−
1.11
x
=
□
\begin{array}{l} \frac{x}{-4}=-1.11 \\ x=\square \end{array}
−
4
x
=
−
1.11
x
=
□
Get tutor help
−
1
2
3
÷
(
−
2
1
5
)
=
-1 \frac{2}{3} \div\left(-2 \frac{1}{5}\right)=
−
1
3
2
÷
(
−
2
5
1
)
=
Get tutor help
−
4
1
2
÷
(
−
1
3
8
)
=
-4 \frac{1}{2} \div\left(-1 \frac{3}{8}\right)=
−
4
2
1
÷
(
−
1
8
3
)
=
Get tutor help
Evaluate and simplify the following complex fraction.
\newline
−
5
−
2
6
7
=
□
\frac{\frac{-5}{-2}}{\frac{6}{7}}=\square
7
6
−
2
−
5
=
□
Get tutor help
0.75
:
0.15
:
0.10
0.75:0.15:0.10
0.75
:
0.15
:
0.10
Get tutor help
nstructions
\newline
Choose the best answer. If necessary, use the pap
\newline
Question
\newline
Which of the following statements is true?
\newline
0.6
<
0.61
<
0.7
0.6<0.61<0.7
0.6
<
0.61
<
0.7
\newline
0.61
<
0.6
<
0.7
0.61<0.6<0.7
0.61
<
0.6
<
0.7
\newline
0.7
<
0.61
<
0.6
0.7<0.61<0.6
0.7
<
0.61
<
0.6
\newline
0.7
<
0.6
<
0.61
0.7<0.6<0.61
0.7
<
0.6
<
0.61
Get tutor help
\begin{tabular}{|c|c|c|}
\newline
\hline
44
44
44
.
5
5
5
&
5
5
5
.
5
5
5
&
?
?
?
\\
\newline
\hline
85
85
85
.
5
5
5
&
(
10.5
)
(10.5)
(
10.5
)
&
14
14
14
\\
\newline
\hline
63
63
63
&
(
3
)
(3)
(
3
)
&
?
?
?
\\
\newline
\hline
19
19
19
&
1
1
1
&
?
?
?
\\
\newline
\hline
77
77
77
.
44
44
44
&
10
10
10
.
56
56
56
&
?
?
?
\\
\newline
\hline
22
22
22
.
22
22
22
&
(
0.22
)
(0.22)
(
0.22
)
&
?
?
?
\\
\newline
\hline
30
30
30
.
96
96
96
&
5
5
5
.
04
04
04
&
?
?
?
\\
\newline
\hline
23
23
23
.
04
04
04
&
0
0
0
.
96
96
96
&
?
?
?
\\
\newline
\hline
\newline
\end{tabular}
Get tutor help
19
19
19
) The value of
y
y
y
varies directly with
x
x
x
. When
y
=
25
,
x
=
3
/
4
y=25, x=3 / 4
y
=
25
,
x
=
3/4
. What is the value of
y
y
y
when
x
x
x
is
4
4
4
.
875
875
875
?
\newline
81
81
81
.
25
25
25
\newline
121
121
121
.
875
875
875
\newline
iv
\newline
103
103
103
.
125
125
125
\newline
162
162
162
.
5
5
5
Get tutor help
356.2
i
m
e
s
5.01
356.2 imes 5.01
356.2
im
es
5.01
Get tutor help
2
×
$
0.36
=
$
0.36
+
$
0.36
=
$
\begin{aligned} 2 \times \$ 0.36 & =\$ 0.36+\$ 0.36 \\ & =\$\end{aligned}
2
×
$0.36
=
$0.36
+
$0.36
=
$
Get tutor help
3
1
4
−
1
3
8
3 \frac{1}{4} -1 \frac{3}{8}
3
4
1
−
1
8
3
=
Get tutor help
Which number is the solution to
n
−
2.7
=
5.4
n-2.7=5.4
n
−
2.7
=
5.4
?
\newline
2
2
2
.
7
7
7
\newline
3
3
3
.
7
7
7
\newline
7
7
7
.
1
1
1
\newline
8
8
8
.
1
1
1
Get tutor help
work:
11.4
11.4
11.4
HW -
\newline
HW Score:
\newline
27.59
%
27.59\%
27.59%
,
8
8
8
of
29
29
29
\newline
Question
9
9
9
,
11.4.3
11.4.3
11.4.3
\newline
points
\newline
Points:
0
0
0
of
1
1
1
\newline
Save
\newline
list
\newline
quad
<
{
:
[
A
< \{:[A
<
{
:
[
A
10
10
10
-sided die is rolled. Find to
27.59
%
27.59\%
27.59%
0
0
0
below.
27.59
%
27.59\%
27.59%
1
1
1
\newline
The probability of rolling an even number on a
10
10
10
-sided die is
\newline
27.59
%
27.59\%
27.59%
3
3
3
.
\newline
(Type an integer or a simplified fraction.)
Get tutor help
14
14
14
. [
0
0
0
/
1
1
1
Points]
\newline
DETAILS
\newline
PREVIOUS ANSWERS
\newline
LARCALCET
6
6
6
9
9
9
.
8
8
8
.
042
042
042
.
\newline
Write an equivalent series with the index of summation beginning at
n
=
1
n=1
n
=
1
.
\newline
∑
n
=
0
∞
(
−
1
)
n
+
1
(
n
+
1
)
x
n
\sum_{n=0}^{\infty}(-1)^{n+1}(n+1) x^{n}
n
=
0
∑
∞
(
−
1
)
n
+
1
(
n
+
1
)
x
n
Get tutor help
Question
7
7
7
,
7
7
7
.
1
1
1
.
33
33
33
\newline
HW Score:
71.43
%
71.43\%
71.43%
,
5
5
5
of
7
7
7
\newline
Part
2
2
2
of
2
2
2
\newline
points
\newline
Points:
0
0
0
of
1
1
1
\newline
Find the missing coordinate to complete the ordered-pair solution to the given linear equation
\newline
5
x
−
4
y
=
27
5x-4y=27
5
x
−
4
y
=
27
\newline
(a)
(
−
1
,
(-1,
(
−
1
,
\newline
(b)
(
,
2
)
(,2)
(
,
2
)
Get tutor help
2
4
3
⋅
2
2
3
2\sqrt[3]{4} \cdot 2\sqrt[3]{2}
2
3
4
⋅
2
3
2
\newline
What is the value of the given expression?
\newline
Choose
1
1
1
answer:
\newline
(A)
2
6
3
2\sqrt[3]{6}
2
3
6
\newline
(B)
4
8
6
4\sqrt[6]{8}
4
6
8
\newline
(C)
8
8
8
\newline
(D)
16
16
16
Get tutor help
Find the product
x
y
xy
x
y
if
\newline
{
2
x
+
3
y
=
5
2
x
+
2
+
3
y
+
1
=
18
\begin{cases} 2^{x}+3^{y}=5 \ 2^{x+2}+3^{y+1}=18 \end{cases}
{
2
x
+
3
y
=
5
2
x
+
2
+
3
y
+
1
=
18
Get tutor help
Which expression has the same value as
53.5
−
(
−
3.7
)
53.5-(-3.7)
53.5
−
(
−
3.7
)
?
\newline
53.5
+
3.7
53.5+3.7
53.5
+
3.7
\newline
−
3.7
−
53.5
-3.7-53.5
−
3.7
−
53.5
\newline
53.5
−
3.7
53.5-3.7
53.5
−
3.7
\newline
3.7
−
53.5
3.7-53.5
3.7
−
53.5
Get tutor help
Which expression is equivalent to
−
1.3
−
(
−
1.9
)
-1.3-(-1.9)
−
1.3
−
(
−
1.9
)
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
1.9
+
1.3
-1.9+1.3
−
1.9
+
1.3
\newline
(B)
−
1.3
+
(
−
1.9
)
-1.3+(-1.9)
−
1.3
+
(
−
1.9
)
\newline
(C)
−
1.3
+
1.9
-1.3+1.9
−
1.3
+
1.9
\newline
(D)
1.3
+
1.9
1.3+1.9
1.3
+
1.9
Get tutor help
Find the difference.
\newline
[
4
−
2
−
1
4
]
−
[
1
0
0
1
]
=
\left[\begin{array}{cc} 4 & -2 \\ -1 & 4 \end{array}\right]-\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]=
[
4
−
1
−
2
4
]
−
[
1
0
0
1
]
=
Get tutor help
Find the sum.
\newline
[
−
2
0
3
−
2
]
+
[
3
−
1
2
0
]
=
\left[\begin{array}{cc} -2 & 0 \\ 3 & -2 \end{array}\right]+\left[\begin{array}{cc} 3 & -1 \\ 2 & 0 \end{array}\right]=
[
−
2
3
0
−
2
]
+
[
3
2
−
1
0
]
=
Get tutor help
Find the product.
\newline
−
1
4
⋅
[
20
−
4
16
−
12
]
=
-\frac{1}{4} \cdot\left[\begin{array}{cc} 20 & -4 \\ 16 & -12 \end{array}\right]=
−
4
1
⋅
[
20
16
−
4
−
12
]
=
Get tutor help
Find the product.
\newline
3
⋅
[
4
−
2
−
1
4
]
=
3 \cdot\left[\begin{array}{cc}4 & -2 \\ -1 & 4\end{array}\right]=
3
⋅
[
4
−
1
−
2
4
]
=
Get tutor help
Find the product.
\newline
−
1
3
⋅
[
3
−
6
−
3
9
]
=
-\frac{1}{3} \cdot\left[\begin{array}{cc} 3 & -6 \\ -3 & 9 \end{array}\right]=
−
3
1
⋅
[
3
−
3
−
6
9
]
=
Get tutor help
Find the product.
\newline
−
2
⋅
[
−
1
3
4
2
]
=
-2 \cdot\left[\begin{array}{cc} -1 & 3 \\ 4 & 2 \end{array}\right]=
−
2
⋅
[
−
1
4
3
2
]
=
Get tutor help
Find the product.
\newline
1
2
⋅
[
−
4
6
2
0
]
=
\frac{1}{2} \cdot\left[\begin{array}{cc} -4 & 6 \\ 2 & 0 \end{array}\right]=
2
1
⋅
[
−
4
2
6
0
]
=
Get tutor help
Find the product.
\newline
1
5
⋅
[
15
−
5
−
10
20
]
=
\frac{1}{5} \cdot\left[\begin{array}{cc} 15 & -5 \\ -10 & 20 \end{array}\right]=
5
1
⋅
[
15
−
10
−
5
20
]
=
Get tutor help
Find the product.
\newline
4
⋅
[
−
1
3
4
1
]
=
4 \cdot\left[\begin{array}{cc}-1 & 3 \\ 4 & 1\end{array}\right]=
4
⋅
[
−
1
4
3
1
]
=
Get tutor help
Find the product.
\newline
−
5
⋅
[
1
0
−
2
−
1
]
=
-5 \cdot\left[\begin{array}{cc} 1 & 0 \\ -2 & -1 \end{array}\right]=
−
5
⋅
[
1
−
2
0
−
1
]
=
Get tutor help
Find the sum.
\newline
[
−
1
4
4
3
]
+
[
3
2
−
2
1
]
=
\left[\begin{array}{cc} -1 & 4 \\ 4 & 3 \end{array}\right]+\left[\begin{array}{cc} 3 & 2 \\ -2 & 1 \end{array}\right]=
[
−
1
4
4
3
]
+
[
3
−
2
2
1
]
=
Get tutor help
Find the sum.
\newline
[
−
1
−
2
−
2
−
1
]
+
[
1
0
2
−
1
]
=
\left[\begin{array}{cc} -1 & -2 \\ -2 & -1 \end{array}\right]+\left[\begin{array}{cc} 1 & 0 \\ 2 & -1 \end{array}\right]=
[
−
1
−
2
−
2
−
1
]
+
[
1
2
0
−
1
]
=
Get tutor help
Find the difference.
\newline
[
−
1
3
4
1
]
−
[
1
4
3
0
]
=
\left[\begin{array}{cc} -1 & 3 \\ 4 & 1 \end{array}\right]-\left[\begin{array}{ll} 1 & 4 \\ 3 & 0 \end{array}\right]=
[
−
1
4
3
1
]
−
[
1
3
4
0
]
=
Get tutor help
Find the sum.
\newline
[
3
1
0
−
2
]
+
[
4
0
3
−
1
]
=
\left[\begin{array}{cc} 3 & 1 \\ 0 & -2 \end{array}\right]+\left[\begin{array}{cc} 4 & 0 \\ 3 & -1 \end{array}\right]=
[
3
0
1
−
2
]
+
[
4
3
0
−
1
]
=
Get tutor help
Find the difference.
\newline
[
0
2
4
4
]
−
[
2
3
−
2
4
]
=
\left[\begin{array}{ll} 0 & 2 \\ 4 & 4 \end{array}\right]-\left[\begin{array}{cc} 2 & 3 \\ -2 & 4 \end{array}\right]=
[
0
4
2
4
]
−
[
2
−
2
3
4
]
=
Get tutor help
Find the difference.
\newline
[
1
0
−
2
−
1
]
−
[
−
1
1
3
−
2
]
=
\left[\begin{array}{cc} 1 & 0 \\ -2 & -1 \end{array}\right]-\left[\begin{array}{cc} -1 & 1 \\ 3 & -2 \end{array}\right]=
[
1
−
2
0
−
1
]
−
[
−
1
3
1
−
2
]
=
Get tutor help
E
=
[
−
1
3
0
4
]
and
B
=
[
0
5
−
2
5
2
2
]
\begin{array}{l} \mathrm{E}=\left[\begin{array}{rr} -1 & 3 \\ 0 & 4 \end{array}\right] \text { and } \mathrm{B}=\left[\begin{array}{llr} 0 & 5 & -2 \\ 5 & 2 & 2 \end{array}\right] \end{array}
E
=
[
−
1
0
3
4
]
and
B
=
[
0
5
5
2
−
2
2
]
\newline
Let
H
=
E
B
\mathrm{H}=\mathrm{EB}
H
=
EB
. Find
H
\mathrm{H}
H
.
\newline
H
=
\mathbf{H}=
H
=
Get tutor help
Evaluate.
\newline
(
−
2
1
4
)
2
=
\left(-2 \frac{1}{4}\right)^{2}=
(
−
2
4
1
)
2
=
Get tutor help
Evaluate.
\newline
(
−
1
1
4
)
2
=
\left(-1 \frac{1}{4}\right)^{2}=
(
−
1
4
1
)
2
=
Get tutor help
Solve for
s
s
s
:
\newline
−
0.2
=
s
+
(
−
0.8
)
s
=
□
\begin{array}{l} -0.2=s+(-0.8) \\ s=\square \end{array}
−
0.2
=
s
+
(
−
0.8
)
s
=
□
Get tutor help
Solve for
d
d
d
:
\newline
d
+
(
−
5.004
)
=
2.826
d
=
□
\begin{array}{l} d+(-5.004)=2.826 \\ d=\square \end{array}
d
+
(
−
5.004
)
=
2.826
d
=
□
Get tutor help
Solve for
q
q
q
:
\newline
−
9
=
q
−
4.8
q
=
□
\begin{array}{l} -9=q-4.8 \\ q=\square \end{array}
−
9
=
q
−
4.8
q
=
□
Get tutor help
Solve for
u
u
u
:
\newline
−
10.74
=
u
−
(
−
11
)
u
=
□
\begin{array}{l} -10.74=u-(-11) \\ u=\square \end{array}
−
10.74
=
u
−
(
−
11
)
u
=
□
Get tutor help
1
2
3
...
4
Next
