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Find the inverse f(x)=x2+8,x>0f(x)=x^2+8, x>0

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Convert equations of parabolas from general to vertex formright chevron icon

Full solution

Q. Find the inverse f(x)=x2+8,x>0f(x)=x^2+8, x>0
  1. Set f(x)f(x) equal to yy: Set f(x)f(x) equal to yy.\newliney=x2+8y = x^2 + 8
  2. Swap x and y: Swap x and y to find the inverse. x=y2+8x = y^2 + 8
  3. Solve for y: Solve for y. y2=x−8y^2 = x - 8
  4. Take square root: Take the square root of both sides, since x>0x > 0, we only consider the positive square root.\newliney=x−8y = \sqrt{x - 8}

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