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Find the equation of the axis of symmetry of the following quadratic equation. f(x)=-x^(2)-2x-3

11. Find the equation of the axis of symmetry of the following quadratic equation.\newlinef(x)=−x2−2x−3 f(x)=-x^{2}-2 x-3

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Q. 11. Find the equation of the axis of symmetry of the following quadratic equation.\newlinef(x)=−x2−2x−3 f(x)=-x^{2}-2 x-3
  1. Find x-coordinate of vertex: Now we have the x-coordinate of the vertex, which is h=−1h = -1. The axis of symmetry is a vertical line that passes through the vertex, so its equation is x=hx = h. Therefore, the equation of the axis of symmetry is x=−1x = -1.

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