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Find the average distance of each data value in the set from the mean.

Numbers of marbles in a bag: 
25,42,61,33,45,50,34,42
Square footages of homes: 
2052,1250,2200,1856,1442

Find and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary.
3. Numbers of Squares in a
4.







Numbers of Desks in a


Classroom






25
25
25
25


25
25
25
25














Heights of Bleachers


(feet)






110
105.4
97.8
100


98.6
112.5
104.6
99.1














Weights of Wrestlers


(pounds)






131.4
130.7
131.2
131.8


130.6
131.9
130.1
129.5





The data shows the prices of five shirts and five pairs of pants.
Shirts: 
$15,$21,$18,$19,$24

Pants: 
$25,$32,$40,$36,$29
Find the MAD of each data set. Then compare their variations.
8. Add or subtract the MAD from the mean in the data set in Exercise 5 .
a. What percent of the values are within one MAD of the mean?
b. What percent of the values are within two MADs of the mean?
c. Which values are more than twice the MAD from the mean?
d. Find the range and interquartile range for the data set. Use these values to give a possible explanation for the answer to part (b).

Find the average distance of each data value in the set from the mean.\newline11. Numbers of marbles in a bag: 25,42,61,33,45,50,34,42 25,42,61,33,45,50,34,42 \newline22. Square footages of homes: 2052,1250,2200,1856,1442 2052,1250,2200,1856,1442 \newlineFind and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary.\newline33. Numbers of Squares in a\newline44.\newline\begin{tabular}{|c|c|c|c|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineNumbers of Desks in a \\\newlineClassroom\newline\end{tabular}} \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline\newline\end{tabular}\newline55.\newline\begin{tabular}{|c|c|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineHeights of Bleachers \\\newline(feet)\newline\end{tabular}} \\\newline\hline 110110 & 105105.44 & 9797.88 & 100100 \\\newline\hline 9898.66 & 112112.55 & 104104.66 & 9999.11 \\\newline\hline\newline\end{tabular}\newline66.\newline\begin{tabular}{|l|l|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineWeights of Wrestlers \\\newline(pounds)\newline\end{tabular}} \\\newline\hline 131131.44 & 130130.77 & 131131.22 & 131131.88 \\\newline\hline 130130.66 & 131131.99 & 130130.11 & 129129.55 \\\newline\hline\newline\end{tabular}\newline77. The data shows the prices of five shirts and five pairs of pants.\newlineShirts: $15,$21,$18,$19,$24 \$ 15, \$ 21, \$ 18, \$ 19, \$ 24 \newlinePants: $25,$32,$40,$36,$29 \$ 25, \$ 32, \$ 40, \$ 36, \$ 29 \newlineFind the MAD of each data set. Then compare their variations.\newline88. Add or subtract the MAD from the mean in the data set in Exercise 55 .\newlinea. What percent of the values are within one MAD of the mean?\newlineb. What percent of the values are within two MADs of the mean?\newlinec. Which values are more than twice the MAD from the mean?\newlined. Find the range and interquartile range for the data set. Use these values to give a possible explanation for the answer to part (b).

Full solution

Q. Find the average distance of each data value in the set from the mean.\newline11. Numbers of marbles in a bag: 25,42,61,33,45,50,34,42 25,42,61,33,45,50,34,42 \newline22. Square footages of homes: 2052,1250,2200,1856,1442 2052,1250,2200,1856,1442 \newlineFind and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary.\newline33. Numbers of Squares in a\newline44.\newline\begin{tabular}{|c|c|c|c|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineNumbers of Desks in a \\\newlineClassroom\newline\end{tabular}} \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline 2525 & 2525 & 2525 & 2525 \\\newline\hline\newline\end{tabular}\newline55.\newline\begin{tabular}{|c|c|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineHeights of Bleachers \\\newline(feet)\newline\end{tabular}} \\\newline\hline 110110 & 105105.44 & 9797.88 & 100100 \\\newline\hline 9898.66 & 112112.55 & 104104.66 & 9999.11 \\\newline\hline\newline\end{tabular}\newline66.\newline\begin{tabular}{|l|l|l|l|}\newline\hline \multicolumn{44}{|c|}{\begin{tabular}{c} \newlineWeights of Wrestlers \\\newline(pounds)\newline\end{tabular}} \\\newline\hline 131131.44 & 130130.77 & 131131.22 & 131131.88 \\\newline\hline 130130.66 & 131131.99 & 130130.11 & 129129.55 \\\newline\hline\newline\end{tabular}\newline77. The data shows the prices of five shirts and five pairs of pants.\newlineShirts: $15,$21,$18,$19,$24 \$ 15, \$ 21, \$ 18, \$ 19, \$ 24 \newlinePants: $25,$32,$40,$36,$29 \$ 25, \$ 32, \$ 40, \$ 36, \$ 29 \newlineFind the MAD of each data set. Then compare their variations.\newline88. Add or subtract the MAD from the mean in the data set in Exercise 55 .\newlinea. What percent of the values are within one MAD of the mean?\newlineb. What percent of the values are within two MADs of the mean?\newlinec. Which values are more than twice the MAD from the mean?\newlined. Find the range and interquartile range for the data set. Use these values to give a possible explanation for the answer to part (b).
  1. Calculate Mean Shirts Prices: Calculate the mean for shirts prices: $15\$15, $21\$21, $18\$18, $19\$19, $24\$24.\newlineMean = (15+21+18+19+24)/5=97/5=19.4(15 + 21 + 18 + 19 + 24) / 5 = 97 / 5 = 19.4
  2. Calculate Mean Pants Prices: Calculate the mean for pants prices: $25\$25, $32\$32, $40\$40, $36\$36, $29\$29.\newlineMean = (25+32+40+36+29)/5=162/5=32.4(25 + 32 + 40 + 36 + 29) / 5 = 162 / 5 = 32.4
  3. Calculate Deviations Shirts: Calculate the deviations from the mean for shirts, then find the absolute values.\newlineDeviations: 1519.415-19.4, 2119.421-19.4, 1819.418-19.4, 1919.419-19.4, 2419.424-19.4\newlineAbsolute deviations: 4.44.4, 1.61.6, 1.41.4, 0.40.4, 4.64.6
  4. Calculate Deviations Pants: Calculate the deviations from the mean for pants, then find the absolute values.\newlineDeviations: (2532.4)(25-32.4), (3232.4)(32-32.4), (4032.4)(40-32.4), (3632.4)(36-32.4), (2932.4)(29-32.4)\newlineAbsolute deviations: 7.47.4, 0.40.4, 7.67.6, 3.63.6, 3.43.4
  5. Calculate MAD Shirts: Calculate the Mean Absolute Deviation (MAD) for shirts.\newlineMAD = (4.4+1.6+1.4+0.4+4.6)/5=12.4/5=2.48(4.4 + 1.6 + 1.4 + 0.4 + 4.6) / 5 = 12.4 / 5 = 2.48
  6. Calculate MAD Pants: Calculate the Mean Absolute Deviation (MAD) for pants. MAD=7.4+0.4+7.6+3.6+3.45=22.45=4.48MAD = \frac{7.4 + 0.4 + 7.6 + 3.6 + 3.4}{5} = \frac{22.4}{5} = 4.48
  7. Interpret MAD Values: Interpret the MAD values. The MAD for shirts is 2.482.48, indicating smaller deviations from the mean compared to pants, which has a MAD of 4.484.48. This suggests that pants prices vary more than shirt prices around their respective means.

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