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Find the aa value of a parabola that has a vertex at (3,4)(-3,-4) and the point (6,254)(-6,-\frac{25}{4}) that lies on the curve.

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Q. Find the aa value of a parabola that has a vertex at (3,4)(-3,-4) and the point (6,254)(-6,-\frac{25}{4}) that lies on the curve.
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineVertex form: y=a(xh)2+ky = a(x-h)^2 + k
  2. Plug in Vertex: Plug in the vertex (3,4)(-3,-4) into the vertex form.\newliney=a(x+3)24y = a(x+3)^2 - 4
  3. Substitute Point for 'a': Substitute the point (6,254)(-6,-\frac{25}{4}) into the equation to find 'a'.\newline254=a(6+3)24-\frac{25}{4} = a(-6+3)^2 - 4
  4. Simplify Equation: Simplify the equation.\newline254=a(3)24-\frac{25}{4} = a(-3)^2 - 4\newline254=9a4-\frac{25}{4} = 9a - 4
  5. Move Terms: Move 4-4 to the left side of the equation.\newline254+4=9a-\frac{25}{4} + 4 = 9a\newline254+164=9a-\frac{25}{4} + \frac{16}{4} = 9a
  6. Combine Fractions: Combine the fractions on the left side.\newline(25+16)/4=9a(-25 + 16)/4 = 9a\newline9/4=9a-9/4 = 9a
  7. Divide to Solve for 'a': Divide both sides by 99 to solve for 'a'.\newline94÷9=a-\frac{9}{4} \div 9 = a\newline94×19=a-\frac{9}{4} \times \frac{1}{9} = a
  8. Multiply Fractions: Multiply the fractions to find aa.a=936a = \frac{-9}{36}a=14a = \frac{-1}{4}

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