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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)+8x+9
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x2+8x+9 y=x^{2}+8 x+9 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x2+8x+9 y=x^{2}+8 x+9 \newlineAnswer: y= y=
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Begin with Quadratic Function: Begin with the given quadratic function.\newlineWe have y=x2+8x+9y = x^2 + 8x + 9.
  3. Find Constant to Complete: Find the constant to complete the square.\newlineTo complete the square, we need to add and subtract the square of half the coefficient of xx. The coefficient of xx is 88, so half of it is 44, and the square of 44 is 1616.
  4. Add and Subtract Constant: Add and subtract the constant inside the equation.\newlineWe add and subtract 1616 inside the equation to complete the square.\newliney=x2+8x+1616+9y = x^2 + 8x + 16 - 16 + 9
  5. Group and Combine: Group the perfect square trinomial and combine the constants.\newliney=(x2+8x+16)7y = (x^2 + 8x + 16) - 7\newlineNow, we can write the perfect square trinomial as a square of a binomial.\newliney=(x+4)27y = (x + 4)^2 - 7
  6. Write in Vertex Form: Write the equation in vertex form.\newlineThe vertex form of the equation is y=(x+4)27y = (x + 4)^2 - 7.

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