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Complete the square to re-write the quadratic function in vertex form:

y=x^(2)-6x+8
Answer: 
y=

Complete the square to re-write the quadratic function in vertex form:\newliney=x26x+8 y=x^{2}-6 x+8 \newlineAnswer: y= y=

Full solution

Q. Complete the square to re-write the quadratic function in vertex form:\newliney=x26x+8 y=x^{2}-6 x+8 \newlineAnswer: y= y=
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Begin with quadratic function: Begin with the given quadratic function.\newlineWe have the quadratic function y=x26x+8y = x^2 - 6x + 8.
  3. Separate constant term: Separate the constant term from the xx-terms.\newlineTo complete the square, we need to isolate the xx-terms. So we write the function as y=(x26x)+8y = (x^2 - 6x) + 8.
  4. Find completing square value: Find the value needed to complete the square.\newlineTo complete the square for the expression x26xx^2 - 6x, we take half of the coefficient of xx, which is 6/2=3-6/2 = -3, and then square it, which gives us (3)2=9(-3)^2 = 9.
  5. Add/subtract value: Add and subtract the value found inside the parentheses.\newlineWe add and subtract the value 99 inside the parentheses to maintain the equality: y=(x26x+99)+8y = (x^2 - 6x + 9 - 9) + 8.
  6. Rewrite with perfect trinomial: Rewrite the equation with a perfect square trinomial.\newlineNow we have a perfect square trinomial inside the parentheses: y=((x3)29)+8y = ((x - 3)^2 - 9) + 8.
  7. Simplify equation: Simplify the equation.\newlineCombine the constants outside the parentheses: y=(x3)21y = (x - 3)^2 - 1.

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