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bar(HD) is the perpendicular bisector of
bar(KY) such that point
D lays on
bar(KY).DK=7y+17,
HY=4y+33,DY=10 y-22, and
HK=6y+7.
a. Find the value of
y.

y=◻
b. What is the length of
bar(KY) ?

KY=

$\bar{HD}$ is the perpendicular bisector of $\bar{KY}$ such that point $D$ lays on $\bar{KY}$ . $DK=7y+17$ , $HY=4y+33$ , $DY=10 y-22$ , and $HK=6y+7$ . a. Find the value of $y$ . $y=$ ◻ b. What is the length of $\bar{KY}$ ? $\bar{KY}$ $1$

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Write equations of cosine functions using properties

Full solution

Q.

\bar{HD}

is the perpendicular bisector of

\bar{KY}

such that point

D

lays on

\bar{KY}

.

DK=7y+17

,

HY=4y+33

,

DY=10 y-22

, and

HK=6y+7

. a. Find the value of

y

.

y=

◻ b. What is the length of

\bar{KY}

?

\bar{KY}

1

Perpendicular Bisector Property: Since $\overline{HD}$ is the perpendicular bisector of $\overline{KY}$ , $DK = KY$ . So, $7y + 17 = 6y + 7$ .
Solving for y: Subtract $6y$ from both sides to get $y + 17 = 7$ .
Final Solution: Subtract $17$ from both sides to find $y = -10$ .

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