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-9i*(6i+8)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$-9 i \cdot(6 i+8)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

-9 i \cdot(6 i+8)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Distribute $-9i$ : Distribute $-9i$ across the terms inside the parentheses $(6i+8)$ . $\newline$ We need to multiply $-9i$ by each term inside the parentheses separately. $\newline$ $-9i \times 6i = -54i^2$ $\newline$ $-9i \times 8 = -72i$
Simplify the product: Simplify the product. $\newline$ We know that $i^2 = -1$ , so we can replace $-54i^2$ with $54$ , because $-54 \times -1 = 54$ . $\newline$ The product is now $54 - 72i$ .
Write the final answer: Write the final answer in the form $a+bi$ . $\newline$ The real part $a$ is $54$ , and the imaginary part $b$ is $-72$ . $\newline$ So the complex number is $54 - 72i$ .

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