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15*(-4i+2)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$15 \cdot(-4 i+2)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

15 \cdot(-4 i+2)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Multiply real part by $15$ : Multiply the real part of the complex number by $15$ . $\newline$ The real part of the complex number is $2$ . Multiplying this by $15$ gives us $30$ . $\newline$ Calculation: $15 \times 2 = 30$
Multiply imaginary part by $15$ : Multiply the imaginary part of the complex number by $15$ . $\newline$ The imaginary part of the complex number is \(-4i＂). Multiplying this by $15$ gives us \(-60i＂). $\newline$ Calculation: \(15 \times ( $-4$ i) = $-60$ i＂)
Combine results to form final complex number: Combine the results from Step $1$ and Step $2$ to form the final complex number. $\newline$ The real part is $30$ and the imaginary part is $-60i$ . Therefore, the final complex number is $30 - 60i$ . $\newline$ Calculation: $30 + (-60i) = 30 - 60i$

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