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Algebra 2
Name
Elizabeth
Torres
Right Triangles
Date 
qquad
PeI
Find the measure of each side indicated. Round to the nearest tenth.
1)

{:[sin 52=(13 )/(x)],[x*7881(13 )/(x)*x],[(7881)/(7881)=(13)/(7881)],[x=16.49]:}

Algebra 22\newlineName\newlineElizabeth\newlineTorres\newlineRight Triangles\newlineDate\newline\quad\newlinePeI\newlineFind the measure of each side indicated. Round to the nearest tenth.\newline11)\newline\begin{align*}\(\newline\sin 52 &= \frac{13}{x} (\newline\)\frac{x}{\cancel{7881}}(13) &= \frac{x}{\cancel{x}} \times x (\newline\)\frac{7881}{7881} &= \frac{13}{7881} (\newline\)x &= 16.49\newline\end{align*}\)

Full solution

Q. Algebra 22\newlineName\newlineElizabeth\newlineTorres\newlineRight Triangles\newlineDate\newline\quad\newlinePeI\newlineFind the measure of each side indicated. Round to the nearest tenth.\newline11)\newline\begin{align*}\(\newline\sin 52 &= \frac{13}{x} (\newline\)\frac{x}{\cancel{7881}}(13) &= \frac{x}{\cancel{x}} \times x (\newline\)\frac{7881}{7881} &= \frac{13}{7881} (\newline\)x &= 16.49\newline\end{align*}\)
  1. Write Equation: First, let's write down the equation given by the problem: sin(52°)=13x.\sin(52°) = \frac{13}{x}.
  2. Multiply Both Sides: Now, we need to solve for xx. To do this, we'll multiply both sides of the equation by xx to get x×sin(52°)=13x \times \sin(52°) = 13.
  3. Isolate xx: Next, we divide both sides by sin(52°)\sin(52°) to isolate xx. So, x=13sin(52°)x = \frac{13}{\sin(52°)}.
  4. Calculate sin(52°)\sin(52°): We'll use a calculator to find the value of sin(52°)\sin(52°). sin(52°)0.7880\sin(52°) \approx 0.7880 (rounded to four decimal places).
  5. Plug in Value: Now, plug the value of sin(52°)\sin(52°) into the equation: x=130.7880x = \frac{13}{0.7880}.
  6. Perform Division: Perform the division to find xx. x16.5x \approx 16.5 (rounded to the nearest tenth).

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