Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

a. A quadratic expression in the form 
a^(2)x^(2)-b^(2) is called a difference of squares. Use a generic rectangle to prove that 
a^(2)x^(2)-b^(2)=(ax-b)(ax+b). Be ready to share your work with the class.
b. A quadratic expression in the form 
a^(2)x^(2)+2abx+b^(2) is called a perfect square trinomial. Use a generic rectangle to prove that 
a^(2)x^(2)+2abx+b^(2)=(ax+b)^(2). Be ready to share your work with the class.

a. A quadratic expression in the form a2x2b2 a^{2} x^{2}-b^{2} is called a difference of squares. Use a generic rectangle to prove that a2x2b2=(axb)(ax+b) a^{2} x^{2}-b^{2}=(a x-b)(a x+b) . Be ready to share your work with the class.\newlineb. A quadratic expression in the form a2x2+2abx+b2 a^{2} x^{2}+2 a b x+b^{2} is called a perfect square trinomial. Use a generic rectangle to prove that a2x2+2abx+b2=(ax+b)2 a^{2} x^{2}+2 a b x+b^{2}=(a x+b)^{2} . Be ready to share your work with the class.

Full solution

Q. a. A quadratic expression in the form a2x2b2 a^{2} x^{2}-b^{2} is called a difference of squares. Use a generic rectangle to prove that a2x2b2=(axb)(ax+b) a^{2} x^{2}-b^{2}=(a x-b)(a x+b) . Be ready to share your work with the class.\newlineb. A quadratic expression in the form a2x2+2abx+b2 a^{2} x^{2}+2 a b x+b^{2} is called a perfect square trinomial. Use a generic rectangle to prove that a2x2+2abx+b2=(ax+b)2 a^{2} x^{2}+2 a b x+b^{2}=(a x+b)^{2} . Be ready to share your work with the class.
  1. Draw Rectangle Sections: Draw a generic rectangle with four sections for the difference of squares.
  2. Label Length and Width: Label the length of the rectangle as aa for the top two sections, and the width as aa for the top two sections, and b-b and bb for the bottom two sections.
  3. Fill in Areas: Fill in the areas of each section: top left is a2x2a^{2}x^{2}, top right is abxabx, bottom left is abx-abx, and bottom right is b2-b^{2}.
  4. Combine Areas: Combine the areas to form the expression: a2x2+abxabxb2a^{2}x^{2} + abx - abx - b^{2}.
  5. Cancel Out Terms: Notice that abxabx and abx-abx cancel each other out, leaving a2x2b2a^{2}x^{2} - b^{2}.
  6. Calculate Area: The length of the rectangle is (ax+b)(ax + b) and the width is (axb)(ax - b), so the area is (axb)(ax+b)(ax - b)(ax + b).
  7. Draw Another Rectangle: Now, draw another generic rectangle for the perfect square trinomial.
  8. Label Length and Width: Label the length of the rectangle as axax and the width as axax for the top two sections, and bb and bb for the bottom two sections.
  9. Fill in Areas: Fill in the areas of each section: top left is a2x2a^{2}x^{2}, top right is abxabx, bottom left is abxabx, and bottom right is $b^{\(2\)}.
  10. Combine Areas: Combine the areas to form the expression: \(a^{2}x^{2} + abx + abx + b^{2}\).
  11. Calculate Area: Notice that \(abx\) and \(abx\) add up to \(2abx\), leaving \(a^{2}x^{2} + 2abx + b^{2}\).
  12. Calculate Area: Notice that \(abx\) and \(abx\) add up to \(2abx\), leaving \(a^{2}x^{2} + 2abx + b^{2}\).The length of the rectangle is \((ax + b)\) and the width is also \((ax + b)\), so the area is \((ax + b)(ax + b)\) or \((ax + b)^{2}\).

More problems from Reflections of functions