a. A quadratic expression in the form a2x2−b2 is called a difference of squares. Use a generic rectangle to prove that a2x2−b2=(ax−b)(ax+b). Be ready to share your work with the class.b. A quadratic expression in the form a2x2+2abx+b2 is called a perfect square trinomial. Use a generic rectangle to prove that a2x2+2abx+b2=(ax+b)2. Be ready to share your work with the class.
Q. a. A quadratic expression in the form a2x2−b2 is called a difference of squares. Use a generic rectangle to prove that a2x2−b2=(ax−b)(ax+b). Be ready to share your work with the class.b. A quadratic expression in the form a2x2+2abx+b2 is called a perfect square trinomial. Use a generic rectangle to prove that a2x2+2abx+b2=(ax+b)2. Be ready to share your work with the class.
Draw Rectangle Sections: Draw a generic rectangle with four sections for the difference of squares.
Label Length and Width: Label the length of the rectangle as a for the top two sections, and the width as a for the top two sections, and −b and b for the bottom two sections.
Fill in Areas: Fill in the areas of each section: top left is a2x2, top right is abx, bottom left is −abx, and bottom right is −b2.
Combine Areas: Combine the areas to form the expression: a2x2+abx−abx−b2.
Cancel Out Terms: Notice that abx and −abx cancel each other out, leaving a2x2−b2.
Calculate Area: The length of the rectangle is (ax+b) and the width is (ax−b), so the area is (ax−b)(ax+b).
Draw Another Rectangle: Now, draw another generic rectangle for the perfect square trinomial.
Label Length and Width: Label the length of the rectangle as ax and the width as ax for the top two sections, and b and b for the bottom two sections.
Fill in Areas: Fill in the areas of each section: top left is a2x2, top right is abx, bottom left is abx, and bottom right is $b^{\(2\)}.
Combine Areas: Combine the areas to form the expression: \(a^{2}x^{2} + abx + abx + b^{2}\).
Calculate Area: Notice that \(abx\) and \(abx\) add up to \(2abx\), leaving \(a^{2}x^{2} + 2abx + b^{2}\).
Calculate Area: Notice that \(abx\) and \(abx\) add up to \(2abx\), leaving \(a^{2}x^{2} + 2abx + b^{2}\).The length of the rectangle is \((ax + b)\) and the width is also \((ax + b)\), so the area is \((ax + b)(ax + b)\) or \((ax + b)^{2}\).