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5(s+3)+2S-1=2(2S-1)+28

5(s+3)+2S−1=2(2S−1)+28 5(s+3)+2 S-1=2(2 S-1)+28

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Full solution

Q. 5(s+3)+2S−1=2(2S−1)+28 5(s+3)+2 S-1=2(2 S-1)+28
  1. Simplify Equations: Simplify both sides of the equation.\newlineLeft side: 5(s+3)+2s−1=5s+15+2s−1=7s+145(s+3) + 2s - 1 = 5s + 15 + 2s - 1 = 7s + 14.\newlineRight side: 2(2s−1)+28=4s−2+28=4s+262(2s - 1) + 28 = 4s - 2 + 28 = 4s + 26.
  2. Set Equal: Set the simplified expressions equal to each other. 7s+14=4s+267s + 14 = 4s + 26.
  3. Isolate Variable Term: Subtract 4s4s from both sides to isolate the variable term on one side.\newline7s−4s+14=4s−4s+267s - 4s + 14 = 4s - 4s + 26,\newline3s+14=263s + 14 = 26.
  4. Subtract to Solve: Subtract 1414 from both sides to solve for ss.\newline3s+14−14=26−14,3s + 14 - 14 = 26 - 14,\newline3s=12.3s = 12.
  5. Divide to Find Value: Divide both sides by 33 to find the value of ss.3s3=123\frac{3s}{3} = \frac{12}{3},s=4s = 4.

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