Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

33. Which of the following is the equation of the parabola described with vertex at (5,3)(5, -3), axis parallel to the yy-axis and passing through the point (1,1)(1, 1)?\newline(a) (x5)2=4(y+3)(x - 5)^2 = 4(y + 3)\newline(b) (x+5)2=4(y3)(x + 5)^2 = 4(y - 3)\newline(c) (y+3)2=4(x5)(y + 3)^2 = 4(x - 5)\newline(d) (y3)2=4(x+5)(y - 3)^2 = 4(x + 5)

Full solution

Q. 33. Which of the following is the equation of the parabola described with vertex at (5,3)(5, -3), axis parallel to the yy-axis and passing through the point (1,1)(1, 1)?\newline(a) (x5)2=4(y+3)(x - 5)^2 = 4(y + 3)\newline(b) (x+5)2=4(y3)(x + 5)^2 = 4(y - 3)\newline(c) (y+3)2=4(x5)(y + 3)^2 = 4(x - 5)\newline(d) (y3)2=4(x+5)(y - 3)^2 = 4(x + 5)
  1. Identify general form: Identify the general form of the equation for a parabola with a vertical axis. The standard form is (xh)2=4p(yk)(x - h)^2 = 4p(y - k), where (h,k)(h, k) is the vertex.
  2. Plug in vertex: Plug in the vertex (5,3)(5, -3) into the equation. This gives us (x5)2=4p(y+3)(x - 5)^2 = 4p(y + 3).
  3. Use point to find pp: Use the point (1,1)(1, 1) to find the value of pp. Substitute x=1x = 1 and y=1y = 1 into the equation: (15)2=4p(1+3)(1 - 5)^2 = 4p(1 + 3).
  4. Simplify and solve for pp: Simplify and solve for pp: 16=4p×416 = 4p \times 4, 16=16p16 = 16p, p=1p = 1.
  5. Substitute pp back: Substitute p=1p = 1 back into the equation: (x5)2=4(1)(y+3)(x - 5)^2 = 4(1)(y + 3), which simplifies to (x5)2=4(y+3)(x - 5)^2 = 4(y + 3).

More problems from Write equations of parabolas in vertex form using properties