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2
2
2
Solve the equation
x
−
3
16
=
4
x
x
−
3
\frac{x-3}{16}=\frac{4 x}{x-3}
16
x
−
3
=
x
−
3
4
x
.
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Math Problems
Algebra 2
Sum of finite series starts from 1
Full solution
Q.
2
2
2
Solve the equation
x
−
3
16
=
4
x
x
−
3
\frac{x-3}{16}=\frac{4 x}{x-3}
16
x
−
3
=
x
−
3
4
x
.
Cross Multiply:
Cross multiply to get rid of the fractions: x\(-3)(x
−
3
-3
−
3
) =
16
16
16
(
4
4
4
x)\
Expand Left Side:
Expand the left side using the FOIL method:
x
2
−
3
x
−
3
x
+
9
=
64
x
x^2 - 3x - 3x + 9 = 64x
x
2
−
3
x
−
3
x
+
9
=
64
x
.
Combine Like Terms:
Combine like terms on the left side:
x
2
−
6
x
+
9
=
64
x
x^2 - 6x + 9 = 64x
x
2
−
6
x
+
9
=
64
x
.
Subtract
64
x
64x
64
x
:
Subtract
64
x
64x
64
x
from both sides to get all
x
x
x
terms on one side:
x
2
−
70
x
+
9
=
0
x^2 - 70x + 9 = 0
x
2
−
70
x
+
9
=
0
.
Use Quadratic Formula:
Try to factor the quadratic, but it doesn't factor nicely. So, use the quadratic formula:
x
=
−
(
−
70
)
±
(
−
70
)
2
−
4
(
1
)
(
9
)
2
×
1
x = \frac{-(-70) \pm \sqrt{(-70)^2 - 4(1)(9)}}{2 \times 1}
x
=
2
×
1
−
(
−
70
)
±
(
−
70
)
2
−
4
(
1
)
(
9
)
.
Simplify Formula:
Simplify inside the square root and the rest of the formula:
x
=
70
±
4900
−
36
2
x = \frac{70 \pm \sqrt{4900 - 36}}{2}
x
=
2
70
±
4900
−
36
.
Further Simplify:
Further simplify the square root:
x
=
70
±
4864
2
x = \frac{70 \pm \sqrt{4864}}{2}
x
=
2
70
±
4864
.
Calculate Square Root:
Calculate the square root:
x
=
70
±
70
2
x = \frac{\sqrt{70} \pm \sqrt{70}}{2}
x
=
2
70
±
70
.
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What kind of sequence is this?
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Choices:Choices:
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∑
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Choices:
\newline
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\text{[A]arithmetic}
[A]arithmetic
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[B]geometric
\text{[B]geometric}
[B]geometric
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[C]both
\text{[C]both}
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Question
Find the first three partial sums of the series.
\newline
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\newline
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S_1 =
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1
=
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\newline
S
2
=
S_2 =
S
2
=
____
\newline
S
3
=
S_3 =
S
3
=
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Find the third partial sum of the series.
\newline
3
+
9
+
15
+
21
+
27
+
33
+
⋯
3 + 9 + 15 + 21 + 27 + 33 + \cdots
3
+
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15
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33
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\newline
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+
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+
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Write your answers as integers or fractions in simplest form.
\newline
S
1
=
S_1 =
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1
=
____
\newline
S
2
=
S_2 =
S
2
=
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\newline
S
3
=
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3
=
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Question
Does the infinite geometric series converge or diverge?
\newline
1
+
3
4
+
9
16
+
27
64
+
⋯
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\newline
Choices:
\newline
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[A]converge
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[B]diverge
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