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{:[{[h(1)=-2],[h(n)=h(n-1)+n]:}],[h(2)=]:}

{h(1)=−2h(n)=h(n−1)+nh(2)=□ \begin{array}{l}\left\{\begin{array}{l}h(1)=-2 \\ h(n)=h(n-1)+n\end{array}\right. \\ h(2)=\square\end{array}

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Q. {h(1)=−2h(n)=h(n−1)+nh(2)=□ \begin{array}{l}\left\{\begin{array}{l}h(1)=-2 \\ h(n)=h(n-1)+n\end{array}\right. \\ h(2)=\square\end{array}
  1. Given recursive formula: We are given the recursive formula for a sequence h(n)h(n):h(1)=−2h(1) = -2h(n)=h(n−1)+nh(n) = h(n-1) + nTo find h(2)h(2), we need to use the value of h(1)h(1) and the recursive formula.h(2)=h(1)+2h(2) = h(1) + 2h(2)=−2+2h(2) = -2 + 2h(2)=0h(2) = 0

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