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(c) The function 
f is defined as 
xrarr(2x)/(x+1), where 
xinR\\{-1}.
(i) Find the equations of the asymptotes of the curve 
y=f(x).
(ii) 
P and 
Q are distinct points on the curve 
y=f(x).
The tangent at 
Q is parallel to the tangent at 
P.
The co-ordinates of 
P are 
(1,1).
Find the co-ordinates of 
Q.
(iii) Verify that the point of intersection of the asymptotes is the midpoint of [PQ].

(c) The function f \mathrm{f} is defined as x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} , where xR\{1} \mathrm{x} \in \mathbb{R} \backslash\{-1\} .\newline(i) Find the equations of the asymptotes of the curve y=f(x) y=f(x) .\newline(ii) P P and Q Q are distinct points on the curve y=f(x) y=f(x) .\newlineThe tangent at Q Q is parallel to the tangent at P P .\newlineThe co-ordinates of P P are x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} 00.\newlineFind the co-ordinates of x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} 11.\newline(iii) Verify that the point of intersection of the asymptotes is the midpoint of [PQ].

Full solution

Q. (c) The function f \mathrm{f} is defined as x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} , where xR\{1} \mathrm{x} \in \mathbb{R} \backslash\{-1\} .\newline(i) Find the equations of the asymptotes of the curve y=f(x) y=f(x) .\newline(ii) P P and Q Q are distinct points on the curve y=f(x) y=f(x) .\newlineThe tangent at Q Q is parallel to the tangent at P P .\newlineThe co-ordinates of P P are x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} 00.\newlineFind the co-ordinates of x2xx+1 \mathrm{x} \rightarrow \frac{2 \mathrm{x}}{\mathrm{x}+1} 11.\newline(iii) Verify that the point of intersection of the asymptotes is the midpoint of [PQ].
  1. Calculate Total Tape: Total tape needed = 8,000cm8,000\,\text{cm}. Each roll contains = 2,000cm2,000\,\text{cm}. Number of rolls needed = Total tape neededEach roll contains\frac{\text{Total tape needed}}{\text{Each roll contains}}.
  2. Calculate Rolls: Calculate the number of rolls: 8,000cm÷2,000cm=48,000\,\text{cm} \div 2,000\,\text{cm} = 4 rolls.

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