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{:[=(3x^(2))/(1)],[" Question "11=3x^(2)],[" Simplify "(7x^(2)y)^(0)÷(4x^(3))^(-1)],[(7x^(2)y)^(0)÷(4x^(3))^(-1)=]:}

=3x21 Question 11=3x2 Simplify (7x2y)0÷(4x3)1(7x2y)0÷(4x3)1= \begin{array}{l}=\frac{3 x^{2}}{1} \\ \text { Question } 11=3 x^{2} \\ \text { Simplify }\left(7 x^{2} y\right)^{0} \div\left(4 x^{3}\right)^{-1} \\ \left(7 x^{2} y\right)^{0} \div\left(4 x^{3}\right)^{-1}=\end{array}

Full solution

Q. =3x21 Question 11=3x2 Simplify (7x2y)0÷(4x3)1(7x2y)0÷(4x3)1= \begin{array}{l}=\frac{3 x^{2}}{1} \\ \text { Question } 11=3 x^{2} \\ \text { Simplify }\left(7 x^{2} y\right)^{0} \div\left(4 x^{3}\right)^{-1} \\ \left(7 x^{2} y\right)^{0} \div\left(4 x^{3}\right)^{-1}=\end{array}
  1. Power of 00 is 11: Anything to the power of 00 is 11.\newline(7x2y)0=1(7x^{2}y)^{0} = 1
  2. Negative Exponent Reciprocal: Negative exponent means reciprocal.\newline(4x3)1=14x3(4x^{3})^{-1} = \frac{1}{4x^{3}}
  3. Divide by Reciprocal: Divide 11 by 1/(4x3)1/(4x^{3}).\newline1÷(1/(4x3))=4x31 \div (1/(4x^{3})) = 4x^{3}

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