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-3(1+6r)=14-r

1111) −3(1+6r)=14−r -3(1+6 r)=14-r

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Full solution

Q. 1111) −3(1+6r)=14−r -3(1+6 r)=14-r
  1. Distribute and Simplify: First, distribute the −3-3 into the parentheses: −3×1+−3×6r=−3−18r-3 \times 1 + -3 \times 6r = -3 - 18r.
  2. Combine Terms: Now we have the equation −3−18r=14−r-3 - 18r = 14 - r.
  3. Isolate Variable: Next, add 18r18r to both sides to get all the rr terms on one side: −3=14−r+18r-3 = 14 - r + 18r.
  4. Subtract and Simplify: Combine like terms on the right side: −3=14+17r-3 = 14 + 17r.
  5. Combine Like Terms: Subtract 1414 from both sides to isolate the term with rr: −3−14=17r-3 - 14 = 17r.
  6. Simplify Left Side: Simplify the left side: −17=17r-17 = 17r.
  7. Divide to Solve: Finally, divide both sides by 1717 to solve for rr: r=−1717.r = -\frac{17}{17}.
  8. Final Answer: Simplify the fraction to get the final answer: r=−1r = -1.

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