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{:[2x+3y=-8],[3y^(2)-8y=2x+10]:}
If 
(x_(1),y_(1)) and 
(x_(2),y_(2)) are distinct solutions to the system of equations shown, what is the product of the 
x_(1) and 
x_(2) ?

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2x+3y=82x+3y=-8 \newline3y28y=2x+103y^{2}-8y=2x+10\newline If (x1,y1)(x_{1},y_{1}) and (x2,y2)(x_{2},y_{2}) are distinct solutions to the system of equations shown, what is the product of the x1x_{1} and x2x_{2}?

Full solution

Q. 2x+3y=82x+3y=-8 \newline3y28y=2x+103y^{2}-8y=2x+10\newline If (x1,y1)(x_{1},y_{1}) and (x2,y2)(x_{2},y_{2}) are distinct solutions to the system of equations shown, what is the product of the x1x_{1} and x2x_{2}?
  1. Solve for x: Solve the first equation for x: 2x=83y2x = -8 - 3y, so x=83y2x = \frac{-8 - 3y}{2}.
  2. Substitute xx: Substitute xx in the second equation: 3y28y=2((83y)/2)+103y^{2} - 8y = 2((-8 - 3y)/2) + 10.
  3. Simplify equation: Simplify the second equation: 3y28y=83y+103y^{2} - 8y = -8 - 3y + 10.
  4. Combine like terms: Combine like terms: 3y25y+8=03y^{2} - 5y + 8 = 0.
  5. Factor quadratic equation: Factor the quadratic equation: (3y8)(y+1)=0(3y - 8)(y + 1) = 0.
  6. Find roots for y: Find the roots for y: y=83y = \frac{8}{3} or y=1y = -1.
  7. Substitute yy into x1x_{1}: Substitute y=83y = \frac{8}{3} into x=83y2x = \frac{-8 - 3y}{2} to find x1x_{1}: x1=83(83)2x_{1} = \frac{-8 - 3(\frac{8}{3})}{2}.
  8. Calculate x1x_{1}: Calculate x1x_{1}: x1=(88)/2=16/2=8x_{1} = (-8 - 8)/2 = -16/2 = -8.
  9. Substitute yy into x2x_{2}: Substitute y=1y = -1 into x=83y2x = \frac{-8 - 3y}{2} to find x2x_{2}: x2=83(1)2x_{2} = \frac{-8 - 3(-1)}{2}.
  10. Calculate x2x_{2}: Calculate x2x_{2}: x2=8+32=52x_{2} = \frac{-8 + 3}{2} = -\frac{5}{2}.
  11. Find product of x1x_{1} and x2x_{2}: Find the product of x1x_{1} and x2x_{2}: (8)×(52)(-8) \times \left(-\frac{5}{2}\right).
  12. Calculate product: Calculate the product: x1×x2=402=20x_{1} \times x_{2} = \frac{40}{2} = 20.

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