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Find probabilities using the binomial distribution

Now- \qquad Dune \qquad Class \qquad \newlinePractice A\newlineTwo-Way Tables\newline11. The table shows the results of a survey of 160160 randomly-selected people entering an amusement pawk who wore asked whether they wore planning to nobe the Monster Loop. a roltercoaster. Make a tabte of joint and meginal relabive frequencies. The tatile has bebn serted for you. started for you.\newline\begin{tabular}{|l|c|c|c|c|}\newline\cline { 22 - 55 } \multicolumn{11}{c|}{} & Ages 88−15-15 & Ages 1616−25-25 & Ages 2626−35-35 & 3636 and Older \\\newline\hline Yes & 1919 & 2323 & 88 & 1414 \\\newline\hline No & 88 & 1111 & 1212 & 55 \\\newline\hline\newline\end{tabular}\newline\begin{tabular}{|l|c|c|c|c|c|}\newline\hline & Ages 88−15-15 & Ages 1616−25-25 & Ages 2626−35-35 & 3636 and Older & Total \\\newline\hline Yes & 00.1919 & & & & 00.6464 \\\newline\hline No & & & & & \\\newline\hline Total & & & & & 11 \\\newline\hline\newline\end{tabular}\newline22. Thomas collected data on 2525 randomly selected 1717-year-clds at his school, and summarized the results in a table.\newlineHas a Driver's License\newlineHas a Job\newline\begin{tabular}{|c|c|c|}\newline\hline & Has a Driver's License \\\newline\hline & Yes & No \\\newline\hline Yes & 99 & 33 \\\newline\hline No & 88 & 55 \\\newline\hline\newline\end{tabular}\newlinea. Make a table of the joint relative frequencies and marginal relative frequencies. Round to the nearest hundredth where appropriate. The table has been started for you.\newlineHas a orivers Lifense\newline\begin{tabular}{|c|c|c|c|c|}\newline\hline & & \multicolumn{33}{|c|}{ Has a Driver's License } \\\newline\hline \multirow{44}{*}{ Has a Job } & & Yes & No & Total \\\newline\hline & Yes & & 00.1212 & \\\newline\hline & No & & & \\\newline\hline & Total & 00.6868 & & 11 \\\newline\hline\newline\end{tabular}\newlineb. If you are given that a 1717 -year-old has a job, what is the probability that the 1717 -year-old also has a driver's license? Divide a joint relative frequency by a marginal relative frequency to find the answer. Round your answer to the nearest hundredth.\newlinec. If you are given that a 1717 -year-old has a driver's license, what is the probability that the 1717-year-old also has a job? Divide a joint relative frequency by a marginal relative frequency to find the answer. Round your answer to the nearest hundredth.\newlinePage 1515
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Name\newline\quad\quad\newlineDate\newline\quad\quad Class \newline\quad\quad\newlinePractice A\newlineTwo-Way Tables\newlineThe table shows the results of a survey of 100100 randomly-selected people entering an amusement park who were asked whether they were planning to ride the Monster Loop, a rollercoaster. Make a table of joint and marginal relative frequencies. The table has been started or you\newline\newlineAges 8−158-15\newlineAges 16−2516-25\newlineAges 26−3526-35\newline3636 and Older\newline\newlineYes\newline1919\newline2323\newline\quad\quad00\newline\quad\quad11\newline\newlineNo\newline\quad\quad00\newline\quad\quad33\newline\quad\quad44\newline\quad\quad55\newline\newline\newline\newlineAges 8−158-15\newlineAges 16−2516-25\newlineAges 26−3526-35\newline3636 and Older\newlineTotal\newline\newlineYes\newline\quad\quad00\newline\newline\quad\quad11\newline\newlineNo\newline\newline\newlineTotal\newline\newline\quad\quad22\newline\newlineThomas collected data on \quad\quad33 randomly selected \quad\quad44-year-olds at his school, and summarized the results in a table.\newlineHas a Driver's License\newlineHas a Job\newline\newlineYes\newlineNo\newline\newlineYes\newline\quad\quad55\newline\quad\quad66\newline\newlineNo\newline\quad\quad00\newline\quad\quad55\newline\newlinea. Make a table of the joint relative frequencies and marginal relative frequencies. Round to the nearest hundredth where appropriate. The table has been started for you.\newlineHas a Driver's License\newlineb. If you are given that a \quad\quad44-year-old has a job, what is the probability that the \quad\quad44-year-old also has a driver's license? Divide a joint relative frequency by a marginal relative frequency to find the answer. Round your answer to the nearest hundredth.\newlinec. If you are given that a \quad\quad44-year-old has a driver's license, what is the probability that the \quad\quad44-year-old also has a job? Divide a joint relative frequency by a marginal relative frequency to find the answer. Round your answer to the nearest hundredth.\newlinePage 10010033
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Clever | Portal\newlineALEKS - Jahmeire Byrd - Leam\newlinewww-awu.aleks.com/alekscgi/x/lsl.exe/1010\_U-IgNsikr77j88P33jH-IQT3434vU8080TVrbEJ33mRw88YqmpbCITJaBajvgokWKzSwZDTjsUzofManNs\newlineNew folder\newlineReading Lesson: 'T-\newlineMy Performance\newlineData Analysis and Probability\newlineProbabilities involving two rolls of a die\newlineJa'hm\newline✓\newlineAn ordinary (fair) die is a cube with the numbers 11 through 66 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.\newlineCompute the probability of each of the following events.\newlineEvent\newlineAA : The sum is greater than 88.\newlineEvent\newlineBB : The sum is an odd number.\newlineWrite your answers as fractions.\newline(a)\newlineP(A)=P(A)=\newline◻\newline(b)\newlineP(B)=P(B)=\newline◻\newlineExplanation\newlineCheck\newlineO 20242024 McGraw Hill LLC. All Rights Reserved. Terms of Use I Privacy Center
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Word | Microsoft 365365\newline11st Corinthians annotated biblic\newlineA\newlineALEKS - Jameson Colley - Learn\newlineByteLearn\newlinehttps://Mww-awu.aleks.com/alekscgi/x/|sl.exe/11o_u-IgNsIkasNW88D88A99PVVRDtYD... Al)\newlineImport favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Graphs\newlineWord problem involving a sine or cosine function: Problem type 22\newline3/5 3 / 5 \newlineJameson\newlineEspañol\newlineA person sitting on a Ferris wheel rises and falls as the wheel turns. Suppose that the person's height above ground is described by the following function.\newlineh(t)=18.6+15.4cos⁡1.3t h(t)=18.6+15.4 \cos 1.3 t \newlineIn this equation, h(t) h(t) is the height above ground in meters, and t t is the time in minutes.\newlineFind the following. If necessary, round to the nearest hundredth.\newlineFrequency of h h □ \square revolutions per minute Maximum height above the ground: □ \square meters Time for one complete revolution: □ \square minutes\newlineExplanation\newlineCheck\newlinec. 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search
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The table below shows length of time that customer take to pay their invoices\newline\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|}\newline\hline \begin{tabular}{l} \newlineNumber of \\\newlinedays\newline\end{tabular} & 1−9 1-9 & 10−19 10-19 & 20−29 20-29 & 30−39 30-39 & 40−49 40-49 & 50−59 50-59 & 60−69 60-69 & 70−79 70-79 & 80−89 80-89 & 90−99 90-99 \\\newline\hline \begin{tabular}{l} \newlineNumber of \\\newlineCustomers\newline\end{tabular} & 77 & 1616 & 2222 & 1818 & 2323 & 99 & 55 & 33 & 22 & 11 \\\newline\hline\newline\end{tabular}\newlineUse the data above to construct a grouped frequency table with the following column headings:\newlinei. Class boundaries\newlineii. Class mid-points\newlineiii. Cumulative frequency\newlineiv. Draw a Histogram to represent the distribution\newlinev. Draw a Cumulative Frequency Curve for the distribution.
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Krystal Ramirez\newline20242024\newlineQuestion 44, 88.22.1111-T\newlineHW Score: 42.86%,3 42.86 \%, 3 of 77 points\newlinePart 44 of 55\newlinePoints: 00 of 11\newlineSave\newlineose a simple random sample of size h=200 \mathrm{h}=200 is obtained from a population whose size is N=20,000 \mathrm{N}=20,000 and whose population proportion with a specified characteristic is p=0.6 p=0.6 . lete parts (a) through (c) below.\newlineNot normal because n≤0.05 N n \leq 0.05 \mathrm{~N} and np(1−p)≥10 n p(1-p) \geq 10 .\newlineApproximately normal because n≤0.05 N n \leq 0.05 \mathrm{~N} and np(1−p)<10 n p(1-p)<10 .\newlineNot normal because n≤0.05 N n \leq 0.05 \mathrm{~N} and np(1−p)<10 n p(1-p)<10 .\newlineApproximately normal because n≤0.05 N n \leq 0.05 \mathrm{~N} and np(1−p)≥10 n p(1-p) \geq 10 .\newlinemine the mean of the sampling distribution of h=200 \mathrm{h}=200 22.\newline66 (Round to one decimal place as needed.)\newlinemine the standard deviation of the sampling distribution of h=200 \mathrm{h}=200 22.\newline0346403464 (Round to six decimal places as fleeded.)\newlinehat is the probability of obtaining h=200 \mathrm{h}=200 44 or more individuals with the characteristic? That is, what is h=200 \mathrm{h}=200 55 ?\newlineh=200 \mathrm{h}=200 66 (Round to four decimal places as needed.)\newlineGet more help\newlineClear all\newlineCheck answe\newlinee\newlineh=200 \mathrm{h}=200 77\newline5353.8585\newlineMean: h=200 \mathrm{h}=200 88\newlineh=200 \mathrm{h}=200 88 Std. Dev.: 052915052915
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At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 1818 minutes and a standard deviation of 22 minutes. What is the probability that a randomly selected customer will have to wait less than 1515 minutes, to the nearest thousandth?
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SP77.44\newlineRaina planted yellow and green squash in her vegetable garden. Then she recorded the length of each squash that she harvested.\newline\begin{tabular}{|c|c|c|}\newline\hline \multicolumn{33}{|c|}{ Length of Yollow Squash (cm) (\mathrm{cm}) } \\\newline\hline 88 & 1010 & 1616 \\\newline\hline 88 & 1212 & 1414 \\\newline\hline 1818 & 2020 & 66 \\\newline\hline\newline\end{tabular}\newline\begin{tabular}{|c|c|c|}\newline\hline \multicolumn{33}{|c|}{ Length of Green Squash (cm) } \\\newline\hline 1414 & 1414 & 1616 \\\newline\hline 1212 & 1414 & 1313 \\\newline\hline 1616 & 1313 & 1414 \\\newline\hline\newline\end{tabular}\newline11. Make a box plot for each data set. Use the number lines provided below.\newline22. Which type of Raina's squash has a higher median length based on the box plots?\newline33. Based on the box plots, which type of Raina's squash would you infer has a more consistent length? Explain your reasoning.\newline44. Based on the box plots, which type of Raina's squash would you infer is generally shorter? Explain your reasoning.
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An art museum recently discovered that 19%19\% of their paintings had been stolen and replaced with replicas. If a tourist observes 22 different paintings at random, what is the probability that exactly 11 is a fake? Write your answer as a decimal rounded to the nearest thousandth.____
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Equation for the approximate line of best fit : y=67x+227 y=\frac{6}{7} x+2 \frac{2}{7} \newline1414) Predict the cost of 88 pounds of strawtoemes.\newline- Graph prediction: \qquad in 99\newline- Equolion prodection :19414 : 19414 show your work:\newline67⋅8+227 \frac{6}{7} \cdot 8+2 \frac{2}{7} \newline1515) Predict the cost of 1414 pounds of strawberries.\newline- Graph prediction : 1/4.50 1 / 4.50 \newline- Equation prediction : $4.29 \$ 4.29 Show your work:\newline67⋅14+227 \frac{6}{7} \cdot 14+2 \frac{2}{7} \newline1616) What does the slope of the line of best fit mean in the context of the given situalion is the slope reasonable in this situgtion? \qquad are about even above and below the slope. \qquad \newline \qquad \newline \qquad \newline \qquad What does the \qquad 00-intercept of the line of best fit mean in the context of the given situation? Is the y-intercept reasonable in this situation? \qquad \newline \qquad \newline0201502015 lindsav Perme\newlinewuw.lindsayperfo.com
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