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During a single day at radio station WMZH, the probability that a particular song is played is 
1//6. What is the probability that this song will be played on exactly 3 days out of 4 days? Round your answer to the nearest thousandth.
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During a single day at radio station WMZH, the probability that a particular song is played is 1/6 1 / 6 . What is the probability that this song will be played on exactly 33 days out of 44 days? Round your answer to the nearest thousandth.\newlineAnswer:

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Q. During a single day at radio station WMZH, the probability that a particular song is played is 1/6 1 / 6 . What is the probability that this song will be played on exactly 33 days out of 44 days? Round your answer to the nearest thousandth.\newlineAnswer:
  1. Understand and Determine Probability: Understand the problem and determine the probability of the song being played on any given day.\newlineThe probability of the song being played on a single day is given as 16\frac{1}{6}. We need to find the probability of this event happening exactly 33 times in a sequence of 44 days.
  2. Use Binomial Probability Formula: Use the binomial probability formula to calculate the probability of the song being played exactly 33 times in 44 days.\newlineThe binomial probability formula is P(X=k)=(nk)pk(1p)nkP(X=k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k}, where:\newline- P(X=k)P(X=k) is the probability of kk successes in nn trials,\newline- (nk)\binom{n}{k} is the binomial coefficient,\newline- pp is the probability of success on a single trial, and\newline- (1p)(1-p) is the probability of failure on a single trial.\newlineIn this case, n=4n=4, 4400, and 4411.
  3. Calculate Binomial Coefficient: Calculate the binomial coefficient (43)\binom{4}{3}.(43)=4!3!(43)!=41=4\binom{4}{3} = \frac{4!}{3! \cdot (4-3)!} = \frac{4}{1} = 4.
  4. Calculate Probability of 33 Times: Calculate the probability of the song being played exactly 33 times.\newlineUsing the binomial probability formula:\newlineP(X=3)=(43)×(16)3×(56)43P(X=3) = \binom{4}{3} \times \left(\frac{1}{6}\right)^3 \times \left(\frac{5}{6}\right)^{4-3}\newlineP(X=3)=4×(16)3×(56)1P(X=3) = 4 \times \left(\frac{1}{6}\right)^3 \times \left(\frac{5}{6}\right)^1
  5. Perform Calculations: Perform the calculations.\newlineP(X=3)=4×(1216)×(56)P(X=3) = 4 \times \left(\frac{1}{216}\right) \times \left(\frac{5}{6}\right)\newlineP(X=3)=4×1216×56P(X=3) = 4 \times \frac{1}{216} \times \frac{5}{6}\newlineP(X=3)=201296P(X=3) = \frac{20}{1296}
  6. Simplify Fraction and Round: Simplify the fraction and round to the nearest thousandth. \newline201296\frac{20}{1296} can be simplified to 5324\frac{5}{324}.\newlineTo round to the nearest thousandth, we convert 5324\frac{5}{324} to a decimal.\newline53240.015432098765432098...\frac{5}{324} \approx 0.015432098765432098...\newlineRounded to the nearest thousandth, this is approximately 0.0150.015.

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