Find probabilities using the binomial distribution

Krystal Ramirez\newline20242024\newlineQuestion 44, 88.22.1111-T\newlineHW Score: 42.86%,3 42.86 \%, 3 of 77 points\newlinePart 44 of 55\newlinePoints: 00 of 11\newlineSave\newlineose a simple random sample of size h=200 \mathrm{h}=200 is obtained from a population whose size is N=20,000 \mathrm{N}=20,000 and whose population proportion with a specified characteristic is p=0.6 p=0.6 . lete parts (a) through (c) below.\newlineNot normal because n0.05 N n \leq 0.05 \mathrm{~N} and np(1p)10 n p(1-p) \geq 10 .\newlineApproximately normal because n0.05 N n \leq 0.05 \mathrm{~N} and np(1p)<10 n p(1-p)<10 .\newlineNot normal because n0.05 N n \leq 0.05 \mathrm{~N} and np(1p)<10 n p(1-p)<10 .\newlineApproximately normal because n0.05 N n \leq 0.05 \mathrm{~N} and np(1p)10 n p(1-p) \geq 10 .\newlinemine the mean of the sampling distribution of h=200 \mathrm{h}=200 22.\newline66 (Round to one decimal place as needed.)\newlinemine the standard deviation of the sampling distribution of h=200 \mathrm{h}=200 22.\newline0346403464 (Round to six decimal places as fleeded.)\newlinehat is the probability of obtaining h=200 \mathrm{h}=200 44 or more individuals with the characteristic? That is, what is h=200 \mathrm{h}=200 55 ?\newlineh=200 \mathrm{h}=200 66 (Round to four decimal places as needed.)\newlineGet more help\newlineClear all\newlineCheck answe\newlinee\newlineh=200 \mathrm{h}=200 77\newline5353.8585\newlineMean: h=200 \mathrm{h}=200 88\newlineh=200 \mathrm{h}=200 88 Std. Dev.: 052915052915
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