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Math Problems
Algebra 2
Evaluate exponential functions
Select the expressions that are equivalent to
5
(
5
c
)
5(5c)
5
(
5
c
)
.
\newline
Multi-select Choices:
\newline
(A)
25
c
25c
25
c
\newline
(B)
5
+
5
c
5 + 5c
5
+
5
c
\newline
(C)
5
(
4
c
+
c
)
5(4c + c)
5
(
4
c
+
c
)
\newline
(D)
(
5
c
)
5
(5c)5
(
5
c
)
5
Get tutor help
If
f
(
x
)
=
e
x
/
8
,
g
(
x
)
=
6
x
+
9
f(x)=e^{x / 8}, g(x)=6 x+9
f
(
x
)
=
e
x
/8
,
g
(
x
)
=
6
x
+
9
, and
h
(
x
)
=
x
h(x)=\sqrt{x}
h
(
x
)
=
x
, Find a simplified formula for:
f
(
g
(
x
)
)
h
(
x
)
=
f(g(x)) h(x)=
f
(
g
(
x
))
h
(
x
)
=
Get tutor help
Let
g
(
x
)
=
3
−
2
x
−
x
3
g(x)=3-2 x-x^{3}
g
(
x
)
=
3
−
2
x
−
x
3
and let
f
f
f
be the inverse function of
g
g
g
. Notice that
g
(
1
)
=
0
g(1)=0
g
(
1
)
=
0
.
\newline
f
′
(
0
)
=
f^{\prime}(0)=
f
′
(
0
)
=
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
8
(
6
)
x
f(x) = 8(6)^x
f
(
x
)
=
8
(
6
)
x
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
6
(
6
)
x
f(x) = 6(6)^x
f
(
x
)
=
6
(
6
)
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
5
(
12
)
x
+
7
f(x) = 5(12)^x + 7
f
(
x
)
=
5
(
12
)
x
+
7
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
11
(
11
)
x
+
12
f(x) = 11(11)^x + 12
f
(
x
)
=
11
(
11
)
x
+
12
\newline
f
(
0
)
=
‾
f(0) = \underline{\hspace{3em}}
f
(
0
)
=
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
2
(
5
)
x
f(x) = 2(5)^x
f
(
x
)
=
2
(
5
)
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
8
x
+
3
f(x) = 8^x + 3
f
(
x
)
=
8
x
+
3
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
9
(
4
)
x
f(x) = 9(4)^x
f
(
x
)
=
9
(
4
)
x
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
4
x
f(x) = 4^x
f
(
x
)
=
4
x
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
4
x
+
4
f(x) = 4^x + 4
f
(
x
)
=
4
x
+
4
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
4
x
+
11
f(x) = 4^x + 11
f
(
x
)
=
4
x
+
11
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
1
2
x
+
6
f(x) = 12^x + 6
f
(
x
)
=
1
2
x
+
6
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
5
(
9
)
x
+
12
f(x) = 5(9)^x + 12
f
(
x
)
=
5
(
9
)
x
+
12
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
8
x
+
10
f(x) = 8^x + 10
f
(
x
)
=
8
x
+
10
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
1
2
x
+
3
f(x) = 12^x + 3
f
(
x
)
=
1
2
x
+
3
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
4
)
f(4)
f
(
4
)
.
\newline
f
(
x
)
=
5
x
f(x) = 5^x
f
(
x
)
=
5
x
\newline
f
(
4
)
=
f(4) =
f
(
4
)
=
_____
Get tutor help
Use the following function rule to find
f
(
4
)
f(4)
f
(
4
)
.
\newline
f
(
x
)
=
5
x
+
5
f(x) = 5^x + 5
f
(
x
)
=
5
x
+
5
\newline
f
(
4
)
=
f(4) =
f
(
4
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
11
(
9
)
x
f(x) = 11(9)^x
f
(
x
)
=
11
(
9
)
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
7
(
5
)
x
+
7
f(x) = 7(5)^x + 7
f
(
x
)
=
7
(
5
)
x
+
7
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
4
(
11
)
x
+
5
f(x) = 4(11)^x + 5
f
(
x
)
=
4
(
11
)
x
+
5
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
4
)
f(4)
f
(
4
)
.
\newline
f
(
x
)
=
6
(
3
)
x
f(x) = 6(3)^x
f
(
x
)
=
6
(
3
)
x
\newline
f
(
4
)
=
f(4) =
f
(
4
)
=
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
4
(
6
)
x
+
2
f(x) = 4(6)^x + 2
f
(
x
)
=
4
(
6
)
x
+
2
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
Use the following function rule to find
f
(
5
)
f(5)
f
(
5
)
.
\newline
f
(
x
)
=
2
x
+
12
f(x) = 2^x + 12
f
(
x
)
=
2
x
+
12
\newline
f
(
5
)
=
f(5) =
f
(
5
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
8
(
5
)
x
+
1
f(x) = 8(5)^x + 1
f
(
x
)
=
8
(
5
)
x
+
1
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
6
(
8
)
x
f(x) = 6(8)^x
f
(
x
)
=
6
(
8
)
x
\newline
f
(
1
)
=
‾
f(1) = \underline{\hspace{3em}}
f
(
1
)
=
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
4
(
8
)
x
+
7
f(x) = 4(8)^x + 7
f
(
x
)
=
4
(
8
)
x
+
7
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
8
(
2
)
x
f(x) = 8(2)^x
f
(
x
)
=
8
(
2
)
x
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
12
(
12
)
x
f(x) = 12(12)^x
f
(
x
)
=
12
(
12
)
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
4
x
+
5
f(x) = 4^x + 5
f
(
x
)
=
4
x
+
5
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
3
(
6
)
x
+
7
f(x) = 3(6)^x + 7
f
(
x
)
=
3
(
6
)
x
+
7
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
9
x
+
6
f(x) = 9^x + 6
f
(
x
)
=
9
x
+
6
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
- Let
g
g
g
be a function such that
g
(
1
)
=
−
2
g(1)=-2
g
(
1
)
=
−
2
and
g
′
(
1
)
=
7
g^{\prime}(1)=7
g
′
(
1
)
=
7
.
\newline
- Let
h
h
h
be the function
h
(
x
)
=
x
h(x)=\sqrt{x}
h
(
x
)
=
x
.
\newline
Let
F
F
F
be a function defined as
F
(
x
)
=
g
(
x
)
⋅
h
(
x
)
F(x)=g(x) \cdot h(x)
F
(
x
)
=
g
(
x
)
⋅
h
(
x
)
.
\newline
F
′
(
1
)
=
F^{\prime}(1)=
F
′
(
1
)
=
Get tutor help
- Let
f
f
f
be a function such that
f
(
2
)
=
3
f(2)=3
f
(
2
)
=
3
and
f
′
(
2
)
=
−
1
f^{\prime}(2)=-1
f
′
(
2
)
=
−
1
.
\newline
- Let
g
g
g
be the function
g
(
x
)
=
x
2
g(x)=x^{2}
g
(
x
)
=
x
2
.
\newline
Let
G
G
G
be a function defined as
G
(
x
)
=
f
(
x
)
⋅
g
(
x
)
G(x)=f(x) \cdot g(x)
G
(
x
)
=
f
(
x
)
⋅
g
(
x
)
.
\newline
G
′
(
2
)
=
G^{\prime}(2)=
G
′
(
2
)
=
Get tutor help
The graph of function
g
g
g
is shown below. Let
h
(
x
)
=
∫
−
1
x
g
(
t
)
d
t
h(x)=\int_{-1}^{x} g(t) d t
h
(
x
)
=
∫
−
1
x
g
(
t
)
d
t
.
\newline
Evaluate
h
(
3
)
h(3)
h
(
3
)
.
\newline
h
(
3
)
=
h(3)=
h
(
3
)
=
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
3
(
4
)
x
f(x) = 3(4)^x
f
(
x
)
=
3
(
4
)
x
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
9
x
+
3
f(x) = 9^x + 3
f
(
x
)
=
9
x
+
3
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
8
(
2
)
x
+
5
f(x) = 8(2)^x + 5
f
(
x
)
=
8
(
2
)
x
+
5
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
6
(
7
)
x
f(x) = 6(7)^x
f
(
x
)
=
6
(
7
)
x
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
6
x
+
9
f(x) = 6^x + 9
f
(
x
)
=
6
x
+
9
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
3
(
8
)
x
+
4
f(x) = 3(8)^x + 4
f
(
x
)
=
3
(
8
)
x
+
4
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
4
(
12
)
x
f(x) = 4(12)^x
f
(
x
)
=
4
(
12
)
x
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Get tutor help
Use the following function rule to find
f
(
5
)
f(5)
f
(
5
)
.
\newline
f
(
x
)
=
12
(
3
)
x
+
2
f(x) = 12(3)^x + 2
f
(
x
)
=
12
(
3
)
x
+
2
\newline
f
(
5
)
=
f(5) =
f
(
5
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
1
2
x
f(x) = 12^x
f
(
x
)
=
1
2
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
3
)
f(3)
f
(
3
)
.
\newline
f
(
x
)
=
9
(
3
)
x
+
10
f(x) = 9(3)^x + 10
f
(
x
)
=
9
(
3
)
x
+
10
\newline
f
(
3
)
=
f(3) =
f
(
3
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
6
x
f(x) = 6^x
f
(
x
)
=
6
x
\newline
f
(
0
)
=
f(0) =
f
(
0
)
=
_____
Get tutor help
Use the following function rule to find
f
(
1
)
f(1)
f
(
1
)
.
\newline
f
(
x
)
=
7
x
+
3
f(x) = 7^x + 3
f
(
x
)
=
7
x
+
3
\newline
f
(
1
)
=
f(1) =
f
(
1
)
=
_____
Get tutor help
Use the following function rule to find
f
(
2
)
f(2)
f
(
2
)
.
\newline
f
(
x
)
=
10
(
2
)
x
f(x) = 10(2)^x
f
(
x
)
=
10
(
2
)
x
\newline
f
(
2
)
=
f(2) =
f
(
2
)
=
_____
Get tutor help
Use the following function rule to find
f
(
0
)
f(0)
f
(
0
)
.
\newline
f
(
x
)
=
10
(
6
)
x
+
12
f(x) = 10(6)^x + 12
f
(
x
)
=
10
(
6
)
x
+
12
\newline
f
(
0
)
=
‾
f(0) = \underline{\hspace{3em}}
f
(
0
)
=
Get tutor help
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