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Use the following function rule to find f(0)f(0).\newlinef(x)=10(6)x+12f(x) = 10(6)^x + 12\newlinef(0)=‾f(0) = \underline{\hspace{3em}}

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Q. Use the following function rule to find f(0)f(0).\newlinef(x)=10(6)x+12f(x) = 10(6)^x + 12\newlinef(0)=‾f(0) = \underline{\hspace{3em}}
  1. Identify Function for f(0)f(0): Identify the function which represents f(0)f(0). Substitute in 00 for xx in f(x)=10(6)x+12f(x) = 10(6)^x + 12. f(0)=10(6)0+12f(0) = 10(6)^0 + 12
  2. Substitute in f(x)f(x): Evaluate 10(6)010(6)^0.\newlineSince any number raised to the power of 00 is 11, we have:\newline10(6)010(6)^0 \newline=10×1= 10 \times 1 \newline=10= 10
  3. Evaluate 10(6)010(6)^0: f(0)=10+12f(0) = 10 + 12\newlineDetermine the value of f(0)f(0).\newlinef(0)=10+12f(0) = 10 + 12\newlinef(0)=22f(0) = 22

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