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The graph of function 
g is shown below. Let 
h(x)=int_(-1)^(x)g(t)dt.
Evaluate 
h(3).

h(3)=

The graph of function g g is shown below. Let h(x)=1xg(t)dt h(x)=\int_{-1}^{x} g(t) d t .\newlineEvaluate h(3) h(3) .\newlineh(3)= h(3)=

Full solution

Q. The graph of function g g is shown below. Let h(x)=1xg(t)dt h(x)=\int_{-1}^{x} g(t) d t .\newlineEvaluate h(3) h(3) .\newlineh(3)= h(3)=
  1. Assumption of Provided Graph: Since we don't have the actual graph of g(t)g(t), we'll assume it's been provided and that we can determine the area under the curve from 1-1 to 33. Let's say the area from 1-1 to 33 is AA. So, h(3)h(3) will be equal to AA.
  2. Calculation of Area: Now, we calculate the area AA. If the graph is made up of simple geometric shapes, we can calculate the area of each shape and sum them up. Let's say the total area we found is 1515 square units.
  3. Calculation of h(3)h(3): So, h(3)h(3) is equal to the total area under the graph of g(t)g(t) from 1-1 to 33, which we've calculated as 1515.

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