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Grade 8
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Linear Relationships And Functions
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Determine If A Relation Is A Function

Determine If A Relation Is A Function Problems

8 questions
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#1 of 8: Mild

Determine if a relation is a function

<p>This table represents a function:</p><TableUIv2 data-props='{ "headers": [ { "value": "`x`" }, { "value": "`y`" } ], "borders": { "rows": [ 5 ], "cols": [ 2 ] }, "rows": [ [ { "value": "`7`" }, { "value": "`0`" } ], [ { "value": "`6`" }, { "value": "`1`" } ], [ { "value": "`5`" }, { "value": "`2`" } ], [ { "value": "`4`" }, { "value": "`3`" } ] ], "border_color": "rgba(0, 0, 0, 1)"}'></TableUIv2 ><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(8,-1)` </li><li> `(7,4)` </li><li> `(6,5)` </li><li> `(3,2)` </li><li> `(1,9)` </li></ul></selectivedisplay>

#2 of 8: Medium

Determine if a relation is a function

<p>This table represents a function:</p><TableUIv2 data-props='{ "headers": [ { "value": "`x`" }, { "value": "`y`" } ], "borders": { "rows": [ 6 ], "cols": [ 2 ] }, "rows": [ [ { "value": "`-10`" }, { "value": "`-10`" } ], [ { "value": "`-9`" }, { "value": "`-7`" } ], [ { "value": "`-8`" }, { "value": "`-3`" } ], [ { "value": "`-7`" }, { "value": "`0`" } ] ], "border_color": "rgba(0, 0, 0, 1)"}'></TableUIv2 ><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(-12,-11)` </li><li> `(-10,-9)` </li><li> `(-7,-4)` </li><li> `(-5,-1)` </li><li> `(4,2)` </li></ul></selectivedisplay>

#3 of 8: Medium

Determine if a relation is a function

<p>This table represents a function:</p><TableUIv2 data-props='{ "headers": [ { "value": "`x`" }, { "value": "`y`" } ], "borders": { "rows": [ 6 ], "cols": [ 2 ] }, "rows": [ [ { "value": "`11`" }, { "value": "`-3`" } ], [ { "value": "`12`" }, { "value": "`-3`" } ], [ { "value": "`13`" }, { "value": "`0`" } ], [ { "value": "`14`" }, { "value": "`4`" } ] ], "border_color": "rgba(0, 0, 0, 1)"}'></TableUIv2 ><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(10,-2)` </li><li> `(11,-4)` </li><li> `(14,1)` </li><li> `(16,5)` </li><li> `(17,6)` </li></ul></selectivedisplay>

#4 of 8: Medium

Determine if a relation is a function

<p>This table represents a function:</p><TableUIv2 data-props='{ "headers": [ { "value": "`x`" }, { "value": "`y`" } ], "borders": { "rows": [ 5 ], "cols": [ 2 ] }, "rows": [ [ { "value": "`-6`" }, { "value": "`-12`" } ], [ { "value": "`-5`" }, { "value": "`-9`" } ], [ { "value": "`-4`" }, { "value": "`-4`" } ], [ { "value": "`-3`" }, { "value": "`-2`" } ] ], "border_color": "rgba(0, 0, 0, 1)"}'></TableUIv2 ><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(-7,-14)` </li><li> `(-5,8)` </li><li> `(-4,3)` </li><li> `(2,6)` </li><li> `(5,4)` </li></ul></selectivedisplay>

#5 of 8: Medium

Determine if a relation is a function

<p>This table represents a function:</p><TableUIv2 data-props='{ "headers": [ { "value": "`x`" }, { "value": "`y`" } ], "borders": { "rows": [ 6 ], "cols": [ 2 ] }, "rows": [ [ { "value": "`-8`" }, { "value": "`-3`" } ], [ { "value": "`-3`" }, { "value": "`-1`" } ], [ { "value": "`0`" }, { "value": "`0`" } ], [ { "value": "`8`" }, { "value": "`7`" } ] ], "border_color": "rgba(0, 0, 0, 1)"}'></TableUIv2 ><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(-9,-4)` </li><li> `(-2,1)` </li><li> `(0,2)` </li><li> `(6,5)` </li><li> `(8,8)` </li></ul></selectivedisplay>

#6 of 8: Spicy

Determine if a relation is a function

<p>This set of ordered pairs represents a function:</p><ul><li>`(-3, 1)`</li><li>` (-2, 3)`</li> <li>`(-1, 3)`</li><li> `(0, -1)`</li></ul><p>Which of the ordered pairs below could we add and still allow the relation to remain a function?</p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li>`(-4, 2)` </li><li>`(-3, 3)` </li> <li>`(-2, 1)` </li><li>`(2, 5)` </li><li>`(3, 6)`</li></ul></selectivedisplay>

#7 of 8: Spicy

Determine if a relation is a function

<p> This set of ordered pairs represents a function: </p><ul><li> `(-20,-18)` </li><li> `(-13,-15)` </li><li> `(-9,-9)` </li><li> `(-3,-9)` </li></ul><p>Which of the ordered pairs below could we add and still allow the relation to remain a function? </p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li> `(-19,-19)` </li><li> `(-15,2)` </li><li> `(-13,-10)` </li><li> `(-1,-6)` </li><li> `(0,2)` </li></ul></selectivedisplay>

#8 of 8: Spicy

Determine if a relation is a function

<p>This set of ordered pairs represents a function:</p><ul><li>`(-11, -11)`</li><li>`(-8, -4)`</li><li>`(8, 2)`</li><li>`(15, 12)`</li></ul><p>Which of the ordered pairs below could we add and still allow the relation to remain a function?</p><selectivedisplay data-props='{"show_in_create":true, "show_in_problem_qa": true}'><ul><li>`(-9, -5)`</li> <li>`(-8, -8)`</li> <li>`(5, 11)`</li> <li>`(8, 8)`</li> <li>`(12, 15)`</li></ul></selectivedisplay>

Relations and functions define the mapping between any two given sets. A set of ordered pairs that shows the relationship between two sets is known as relation. Function is a subset of relation. Thus, we can say that all functions are relations but all relations are not functions. One basic difference between a function and a relation is that the relation can have different outputs for a single input. However, a function only has a single output for a single input. 

Share determine if a relation is a function problems with your students to make them understand in them about the concepts of relations and functions so that they can clearly define whether a relation is a function. You can also try our Determine If A Relation Is A Function Worksheet and Determine If A Relation Is A Function Quiz as well for a better understanding of the concepts.

Relations and functions define the mapping between any two given sets. A set of ordered pairs that shows the relationship between two sets is known as relation. Function is a subset of relation. Thus, we can say that all functions are relations but all relations are not functions. One basic difference between a function and a relation is that the relation can have different outputs for a single input. However, a function only has a single output for a single input. 

Share determine if a relation is a function problems with your students to make them understand in them about the concepts of relations and functions so that they can clearly define whether a relation is a function. You can also try our Determine If A Relation Is A Function Worksheet and Determine If A Relation Is A Function Quiz as well for a better understanding of the concepts.

Relations and functions define the mapping between any two given sets. A set of ordered pairs that shows the relationship between two sets is known as relation. Function is a subset of relation. Thus, we can say that all functions are relations but all relations are not functions. One basic difference between a function and a relation is that the relation can have different outputs for a single input. However, a function only has a single output for a single input. 

Share determine if a relation is a function problems with your students t...

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Grade 8
Linear Relationships And Functions
8.F.A.1

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What teachers are saying about BytelearnWhat teachers are saying

stephan.png
Stephen Abate
19-year math teacher
Carmel, CA
Any math teacher that I know would love to have access to ByteLearn.
jennifer.png
Jennifer Maschino
4-year math teacher
Summerville, SC
“I love that ByteLearn helps reduce a teacher’s workload and engages students through an interactive digital interface.”
rodolpho.png
Rodolpho Loureiro
Dean, math program manager, principal
Miami, FL
“ByteLearn provides instant, customized feedback for students—a game-changer to the educational landscape.”