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Let’s check out your problem:

\begin{tabular}{|l|l|}$\newline$\hline You get this: & Fill in this: \\$\newline$\hline$y=-x^{2}-6 x+16$ & Either form of the equation other than standard form: \\$\newline$\cline { $1$ - $2$ } & Vertex of the parabola: \\$\newline$\cline { $2$ - $2$ } & $x$-intercepts and $y$-intercept: \\$\newline$\hline$\newline$\end{tabular}