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y=-x^(2)+2x+3

y=−x2+2x+3 y=-x^{2}+2 x+3

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Full solution

Q. y=−x2+2x+3 y=-x^{2}+2 x+3
  1. Plug in x=0x = 0: First, let's plug in x=0x = 0 into the equation y=−x2+2x+3y = -x^2 + 2x + 3.\newliney=−(0)2+2(0)+3y = -(0)^2 + 2(0) + 3
  2. Simplify the equation: Now, simplify the equation.\newliney=−0+0+3y = -0 + 0 + 3
  3. Find yy: Finally, add up the numbers to find yy.y=3y = 3

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