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Math Problems
Algebra 2
Composition of linear and quadratic functions: find a value
Напишите уравнение касательной в точке пересечения графи функции с осью АБЦИсс
\newline
f
(
x
)
=
x
−
1
x
2
+
1
f(x)=\frac{x-1}{x^{2}+1}
f
(
x
)
=
x
2
+
1
x
−
1
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y
=
−
2
(
x
−
1
)
+
3
y=-2^{(x-1)}+3
y
=
−
2
(
x
−
1
)
+
3
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Find
y
′
′
y^{\prime \prime}
y
′′
if
x
4
+
y
4
=
16
x^{4}+y^{4}=16
x
4
+
y
4
=
16
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h
(
x
)
=
x
2
+
k
x
−
4
;
h
(
−
3
)
=
−
7
h(x)=x^2+kx-4;h(-3)=-7
h
(
x
)
=
x
2
+
k
x
−
4
;
h
(
−
3
)
=
−
7
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X
2
+
6
−
8
=
0
X^2+6-8=0
X
2
+
6
−
8
=
0
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calculer le produit de
A
B
T
AB^T
A
B
T
quand
A
=
(
−
1
0
3
2
)
;
B
=
(
4
−
3
0
2
1
0
)
A = \begin{pmatrix} -1 & 0 \ 3 & 2 \end{pmatrix} ;B = \begin{pmatrix} 4 & -3 \ 0 & 2 \ 1 & 0 \end{pmatrix}
A
=
(
−
1
0
3
2
)
;
B
=
(
4
−
3
0
2
1
0
)
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3
B
−
2
C
3B-2C
3
B
−
2
C
quand
B
=
∣
4
−
3
0
2
1
0
∣
;
C
=
∣
1
0
2
4
0
−
3
∣
B = \begin{vmatrix} 4 & -3 \ 0 & 2 \ 1 & 0 \end{vmatrix} ;C= \begin{vmatrix} 1 & 0 \ 2 & 4 \ 0 & -3 \end{vmatrix}
B
=
∣
∣
4
−
3
0
2
1
0
∣
∣
;
C
=
∣
∣
1
0
2
4
0
−
3
∣
∣
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d
y
d
x
=
y
−
1
x
−
3
\frac{dy}{dx}=y^{-1}x^{-3}
d
x
d
y
=
y
−
1
x
−
3
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Solve the Equation using
\newline
9.
9.
9.
\newline
x
2
+
6
=
0
x^{2}+6=0
x
2
+
6
=
0
\newline
−
6
−
6
-6-6
−
6
−
6
\newline
(
x
=
−
6
)
/
(
2
)
(x=-6)/(2)
(
x
=
−
6
)
/
(
2
)
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=
3
x
2
−
8
x
+
2
=
0
=3 x^{2}-8 x+2=0
=
3
x
2
−
8
x
+
2
=
0
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−
3
x
2
+
17
x
−
20
=
-3 x^{2}+17 x-20=
−
3
x
2
+
17
x
−
20
=
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=
x
−
y
=
3
x
2
+
y
2
=
41
=\begin{array}{c} x-y=3 \\ x^{2}+y^{2}=41 \end{array}
=
x
−
y
=
3
x
2
+
y
2
=
41
\newline
substitution mernod
\newline
)
2
+
y
2
=
9
)^{2}+y^{2}=9
)
2
+
y
2
=
9
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s irrational answers
\newline
6
6
6
.
r
2
−
8
r
+
8
=
0
r^{2}-8 r+8=0
r
2
−
8
r
+
8
=
0
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−
4
∣
−
2
x
+
6
∣
=
−
24
?
-4|-2 x+6|=-24 ?
−
4∣
−
2
x
+
6∣
=
−
24
?
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n
\mathrm{n}
n
for all values of
x
\mathrm{x}
x
by completing the
s
q
s q
s
q
\newline
x
2
+
89
=
−
20
x
x^{2}+89=-20 x
x
2
+
89
=
−
20
x
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is
27
y
6
+
512
z
4
27y^6+512z^4
27
y
6
+
512
z
4
a sum of two cubes
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If
x
x
x
is an integer such that
(
−
5
)
6
x
=
5
10
+
x
(-5)^{6x} = 5^{10 + x}
(
−
5
)
6
x
=
5
10
+
x
, what is the value of
x
x
x
?
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Question
\newline
Given
m
∥
n
m \| n
m
∥
n
, find the value of
x
\mathrm{x}
x
.
\newline
Answer
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s
=
18
c
m
,
θ
=
5
4
∘
;
\mathrm{s}=18 \mathrm{~cm}, \theta=54^{\circ} ;
s
=
18
cm
,
θ
=
5
4
∘
;
find
r
\mathrm{r}
r
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=
2
π
J
⋅
(
1
+
e
−
J
3
)
=
=2 \pi J \cdot\left(1+\frac{e^{-J}}{3}\right)=
=
2
π
J
⋅
(
1
+
3
e
−
J
)
=
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=
2
π
J
⋅
1
+
e
−
J
x
=
=2 \pi J \cdot 1+\frac{e^{-J}}{x}=
=
2
π
J
⋅
1
+
x
e
−
J
=
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=
2
π
V
∗
1
+
(
e
−
J
2
)
=
=2\pi V*1+\left(\frac{e^{-J}}{2}\right)=
=
2
πV
∗
1
+
(
2
e
−
J
)
=
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=
2
π
⋅
1
⋅
1
+
e
−
J
2
=
=2 \pi \cdot 1 \cdot 1+\frac{e^{-J}}{2}=
=
2
π
⋅
1
⋅
1
+
2
e
−
J
=
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(
x
+
a
)
2
=
b
(x+a)^2=b
(
x
+
a
)
2
=
b
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www-awu.aleks.com/alekscgi/x/lsl.exe/
1
1
1
o_u-lgNslkrTJ
8
8
8
P
3
3
3
jH-lixk
\newline
Gmail
\newline
YouTube
\newline
Maps
\newline
Welcome - my.cnm...
\newline
Macmillan: Library
\newline
Review for Challenge Exam
\newline
Question
1
1
1
of
33
33
33
(
1
1
1
point) | Question Attempt:
1
1
1
of Unlim
\newline
≡
1
\equiv 1
≡
1
\newline
2
2
2
\newline
3
3
3
\newline
4
4
4
\newline
Incorrect
\newline
Your answer is incorrect.
\newline
Evaluate the following.
\newline
7
+
3
×
7
+
15
÷
5
7+3 \times 7+15 \div 5
7
+
3
×
7
+
15
÷
5
\newline
□
\square
□
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WK
14
14
14
ExponentialEquationsPart
6
6
6
: Question
3
3
3
\newline
3
3
3
). Given that
1
6
−
3
k
−
2
=
6
4
4
k
+
3
25
6
2
k
+
3
6
4
2
k
−
3
16^{-3 k-2}=64^{4 k+3} 256^{2 k+3} 64^{2 k-3}
1
6
−
3
k
−
2
=
6
4
4
k
+
3
25
6
2
k
+
3
6
4
2
k
−
3
, what is the value of
k
k
k
?
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prove that the even power of a natural number cannot be equal to
8
k
−
3
8k-3
8
k
−
3
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prove that the paired degree cannot be equal to
8
k
−
3
8k-3
8
k
−
3
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Find the value of
x
x
x
; if
x
=
(
2
×
3
)
+
11
x = (2 \times 3) + 11
x
=
(
2
×
3
)
+
11
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(b)
9
x
+
3
≥
5
x
−
11
9 x+3 \geq 5 x-11
9
x
+
3
≥
5
x
−
11
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f
(
x
)
=
(
1
−
2
x
)
4
(
x
2
−
1
)
8
f(x) = (1-2x)^4 \sqrt{(x^2-1)^8}
f
(
x
)
=
(
1
−
2
x
)
4
(
x
2
−
1
)
8
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If
10
=
x
10
10=\frac{x}{10}
10
=
10
x
, what is the value of
x
x
x
?
\newline
□
\square
□
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f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
4
f(x) = x^3 + px^2 + qx + 4
f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
4
Get tutor help
4
x
2
+
8
x
+
3
=
4 x^{2}+8 x+3=
4
x
2
+
8
x
+
3
=
Get tutor help
1
1
1
.
9
n
+
3
n
9^{n}+3^{n}
9
n
+
3
n
is divisible by
6
6
6
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y
=
−
x
2
+
2
x
+
3
y=-x^{2}+2 x+3
y
=
−
x
2
+
2
x
+
3
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−
a
⋅
□
=
c
-a \cdot \square=c
−
a
⋅
□
=
c
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x
2
=
202
4
2024
log
64
,
x
=
?
x^2 = 2024^{2024} \log 64, x=?
x
2
=
202
4
2024
lo
g
64
,
x
=
?
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2
x
(
x
−
3
)
=
x
2
−
9
2 x(x-3)=x^{2}-9
2
x
(
x
−
3
)
=
x
2
−
9
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If
f
(
x
)
=
g
(
x
)
h
(
x
)
f(x)=\frac{g(x)}{h(x)}
f
(
x
)
=
h
(
x
)
g
(
x
)
, then
\newline
f
′
(
1
)
=
f^{\prime}(1)=
f
′
(
1
)
=
\newline
Submit Question
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f
(
x
,
y
)
=
x
2
+
y
2
+
4
x
y
+
4
x
+
5
y
+
1
=
f(x, y)=x^{2}+y^{2}+4 x y+4 x+5 y+1=
f
(
x
,
y
)
=
x
2
+
y
2
+
4
x
y
+
4
x
+
5
y
+
1
=
Get tutor help
2
2
2
.
y
=
3
x
2
−
6
x
+
1
y=3 x^{2}-6 x+1
y
=
3
x
2
−
6
x
+
1
.
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Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
10
x
+
9
(
2
x
+
1
)
=
−
7
(
−
4
x
−
2
)
−
5
10 x+9(2 x+1)=-7(-4 x-2)-5
10
x
+
9
(
2
x
+
1
)
=
−
7
(
−
4
x
−
2
)
−
5
\newline
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x
2
+
5
x
+
6
=
0
x
=
?
x^{2}+5 x+6=0 \quad x=?
x
2
+
5
x
+
6
=
0
x
=
?
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4
x
2
+
5
x
+
20
=
0
x
=
?
4 x^{2}+5 x+20=0 \quad x=?
4
x
2
+
5
x
+
20
=
0
x
=
?
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8
8
8
. Given
f
−
1
(
x
)
=
6
x
+
7
f^{-1}(x)=6 x+7
f
−
1
(
x
)
=
6
x
+
7
, Find
f
f
f
.
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Show that
3
2
x
−
1
=
9
x
3
3^{2x - 1} = \frac{9^x}{3}
3
2
x
−
1
=
3
9
x
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oints
\newline
100
100
100
\newline
Submitting an external tool
\newline
Attempts
0
0
0
\newline
Allowed A
\newline
This is the only question in this section.
\newline
Question
\newline
Watch Video
\newline
Given
f
(
x
)
=
−
x
2
−
7
x
f(x)=-x^{2}-7 x
f
(
x
)
=
−
x
2
−
7
x
, find
f
(
−
10
)
f(-10)
f
(
−
10
)
\newline
Answer Attempt
1
1
1
out of
2
2
2
\newline
□
\square
□
\newline
Sign out
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3
y
=
3
2
3 y=\frac{3}{2}
3
y
=
2
3
, value of
y
y
y
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(
−
2
)
2
n
=
16
(-2)^{2n} = 16
(
−
2
)
2
n
=
16
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1
2
3
...
4
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