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Math Problems
Algebra 2
Composition of linear and quadratic functions: find a value
s
=
18
c
m
,
θ
=
5
4
∘
;
\mathrm{s}=18 \mathrm{~cm}, \theta=54^{\circ} ;
s
=
18
cm
,
θ
=
5
4
∘
;
find
r
\mathrm{r}
r
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=
2
π
J
⋅
(
1
+
e
−
J
3
)
=
=2 \pi J \cdot\left(1+\frac{e^{-J}}{3}\right)=
=
2
π
J
⋅
(
1
+
3
e
−
J
)
=
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=
2
π
J
⋅
1
+
e
−
J
x
=
=2 \pi J \cdot 1+\frac{e^{-J}}{x}=
=
2
π
J
⋅
1
+
x
e
−
J
=
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Simplifying the Expression:
2
π
V
∗
1
+
(
e
−
J
2
)
2\pi V*1+\left(\frac{e^{-J}}{2}\right)
2
πV
∗
1
+
(
2
e
−
J
)
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=
2
π
⋅
1
⋅
1
+
e
−
J
2
=
=2 \pi \cdot 1 \cdot 1+\frac{e^{-J}}{2}=
=
2
π
⋅
1
⋅
1
+
2
e
−
J
=
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(
x
+
a
)
2
=
b
(x+a)^2=b
(
x
+
a
)
2
=
b
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www-awu.aleks.com/alekscgi/x/lsl.exe/
1
1
1
o_u-lgNslkrTJ
8
8
8
P
3
3
3
jH-lixk
\newline
Gmail
\newline
YouTube
\newline
Maps
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Welcome - my.cnm...
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Macmillan: Library
\newline
Review for Challenge Exam
\newline
Question
1
1
1
of
33
33
33
(
1
1
1
point) | Question Attempt:
1
1
1
of Unlim
\newline
≡
1
\equiv 1
≡
1
\newline
2
2
2
\newline
3
3
3
\newline
4
4
4
\newline
Incorrect
\newline
Your answer is incorrect.
\newline
Evaluate the following.
\newline
7
+
3
×
7
+
15
÷
5
7+3 \times 7+15 \div 5
7
+
3
×
7
+
15
÷
5
\newline
□
\square
□
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WK
14
14
14
ExponentialEquationsPart
6
6
6
: Question
3
3
3
\newline
3
3
3
). Given that
1
6
−
3
k
−
2
=
6
4
4
k
+
3
25
6
2
k
+
3
6
4
2
k
−
3
16^{-3 k-2}=64^{4 k+3} 256^{2 k+3} 64^{2 k-3}
1
6
−
3
k
−
2
=
6
4
4
k
+
3
25
6
2
k
+
3
6
4
2
k
−
3
, what is the value of
k
k
k
?
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prove that the even power of a natural number cannot be equal to
8
k
−
3
8k-3
8
k
−
3
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prove that the paired degree cannot be equal to
8
k
−
3
8k-3
8
k
−
3
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Find the value of
x
x
x
; if
x
=
(
2
×
3
)
+
11
x = (2 \times 3) + 11
x
=
(
2
×
3
)
+
11
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(b)
9
x
+
3
≥
5
x
−
11
9 x+3 \geq 5 x-11
9
x
+
3
≥
5
x
−
11
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f
(
x
)
=
(
1
−
2
x
)
4
(
x
2
−
1
)
8
f(x) = (1-2x)^4 \sqrt{(x^2-1)^8}
f
(
x
)
=
(
1
−
2
x
)
4
(
x
2
−
1
)
8
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If
10
=
x
10
10=\frac{x}{10}
10
=
10
x
, what is the value of
x
x
x
?
\newline
□
\square
□
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f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
4
f(x) = x^3 + px^2 + qx + 4
f
(
x
)
=
x
3
+
p
x
2
+
q
x
+
4
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4
x
2
+
8
x
+
3
=
4 x^{2}+8 x+3=
4
x
2
+
8
x
+
3
=
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1
1
1
.
9
n
+
3
n
9^{n}+3^{n}
9
n
+
3
n
is divisible by
6
6
6
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y
=
−
x
2
+
2
x
+
3
y=-x^{2}+2 x+3
y
=
−
x
2
+
2
x
+
3
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−
a
⋅
□
=
c
-a \cdot \square=c
−
a
⋅
□
=
c
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x
2
=
202
4
2024
log
64
,
x
=
?
x^2 = 2024^{2024} \log 64, x=?
x
2
=
202
4
2024
lo
g
64
,
x
=
?
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2
x
(
x
−
3
)
=
x
2
−
9
2 x(x-3)=x^{2}-9
2
x
(
x
−
3
)
=
x
2
−
9
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If
f
(
x
)
=
g
(
x
)
h
(
x
)
f(x)=\frac{g(x)}{h(x)}
f
(
x
)
=
h
(
x
)
g
(
x
)
, then
\newline
f
′
(
1
)
=
f^{\prime}(1)=
f
′
(
1
)
=
\newline
Submit Question
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f
(
x
,
y
)
=
x
2
+
y
2
+
4
x
y
+
4
x
+
5
y
+
1
=
f(x, y)=x^{2}+y^{2}+4 x y+4 x+5 y+1=
f
(
x
,
y
)
=
x
2
+
y
2
+
4
x
y
+
4
x
+
5
y
+
1
=
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2
2
2
.
y
=
3
x
2
−
6
x
+
1
y=3 x^{2}-6 x+1
y
=
3
x
2
−
6
x
+
1
.
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Solve the following equation for
x
x
x
. Express your answer in the simplest form.
\newline
10
x
+
9
(
2
x
+
1
)
=
−
7
(
−
4
x
−
2
)
−
5
10 x+9(2 x+1)=-7(-4 x-2)-5
10
x
+
9
(
2
x
+
1
)
=
−
7
(
−
4
x
−
2
)
−
5
\newline
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x
2
+
5
x
+
6
=
0
x
=
?
x^{2}+5 x+6=0 \quad x=?
x
2
+
5
x
+
6
=
0
x
=
?
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4
x
2
+
5
x
+
20
=
0
x
=
?
4 x^{2}+5 x+20=0 \quad x=?
4
x
2
+
5
x
+
20
=
0
x
=
?
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8
8
8
. Given
f
−
1
(
x
)
=
6
x
+
7
f^{-1}(x)=6 x+7
f
−
1
(
x
)
=
6
x
+
7
, Find
f
f
f
.
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Show that
3
2
x
−
1
=
9
x
3
3^{2x - 1} = \frac{9^x}{3}
3
2
x
−
1
=
3
9
x
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oints
\newline
100
100
100
\newline
Submitting an external tool
\newline
Attempts
0
0
0
\newline
Allowed A
\newline
This is the only question in this section.
\newline
Question
\newline
Watch Video
\newline
Given
f
(
x
)
=
−
x
2
−
7
x
f(x)=-x^{2}-7 x
f
(
x
)
=
−
x
2
−
7
x
, find
f
(
−
10
)
f(-10)
f
(
−
10
)
\newline
Answer Attempt
1
1
1
out of
2
2
2
\newline
□
\square
□
\newline
Sign out
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3
y
=
3
2
3 y=\frac{3}{2}
3
y
=
2
3
, value of
y
y
y
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(
−
2
)
2
n
=
16
(-2)^{2n} = 16
(
−
2
)
2
n
=
16
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If
2
×
5
=
9
2 \times 5=9
2
×
5
=
9
and
4
×
0
=
16
4 \times 0=16
4
×
0
=
16
and
8
×
3
=
67
8 \times 3=67
8
×
3
=
67
, and
3
×
8
=
17
3 \times 8=17
3
×
8
=
17
, what is the value of
8
×
8
?
8 \times 8 ?
8
×
8
?
\newline
(A)
64
64
64
\newline
(B)
65
65
65
\newline
(C)
66
66
66
\newline
(D)
72
72
72
\newline
(E)
68
68
68
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If
f
(
x
)
=
(
x
−
2
)
2
−
x
3
f(x)=(x-2)^{2}-x^{3}
f
(
x
)
=
(
x
−
2
)
2
−
x
3
, what is
f
(
−
3
)
−
f
(
3
)
?
f(-3)-f(3) ?
f
(
−
3
)
−
f
(
3
)?
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If
3
x
2
−
18
x
−
15
=
0
3 x^{2}-18 x-15=0
3
x
2
−
18
x
−
15
=
0
, what is the value of
x
2
−
6
x
x^{2}-6 x
x
2
−
6
x
?
\newline
□
\square
□
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Calculate
5.76
+
2.
8
3
\sqrt{5.76}+2.8^{3}
5.76
+
2.
8
3
.
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−
22
≤
x
+
8
-22 \leq x+8
−
22
≤
x
+
8
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y
=
5
(
x
−
2
)
2
−
4
y=5(x-2)^2-4
y
=
5
(
x
−
2
)
2
−
4
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y
=
2
(
x
−
3
)
2
+
5
y=2(x-3)^2+5
y
=
2
(
x
−
3
)
2
+
5
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F
(
x
)
=
x
3
+
8
F(x)=x^3+8
F
(
x
)
=
x
3
+
8
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8
d
÷
−
4
8 d \div-4
8
d
÷
−
4
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(P) Proofreading Pal
\newline
1
1
1
.
4
x
+
8
=
x
−
1
4 x+8=x-1
4
x
+
8
=
x
−
1
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What are the solutions to
25
x
2
=
49
?
25 x^{2}=49 ?
25
x
2
=
49
?
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what is the vertext of
x
2
+
4
x
−
5
x^2+4x-5
x
2
+
4
x
−
5
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Solve for the exact value of
x
x
x
.
\newline
6
ln
(
8
x
−
5
)
+
10
=
52
6 \ln (8 x-5)+10=52
6
ln
(
8
x
−
5
)
+
10
=
52
\newline
Answer:
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.
145
=
5
x
÷
345
+
x
.145=5x\div345+x
.145
=
5
x
÷
345
+
x
Get tutor help
Name:
\newline
5
5
5
.
5
5
5
/
5
5
5
.
6
6
6
Performance Task
\newline
1
1
1
. If
f
(
x
)
=
2
x
−
4
f(x)=2 x-4
f
(
x
)
=
2
x
−
4
and
g
(
x
)
=
x
2
+
1
g(x)=x^{2}+1
g
(
x
)
=
x
2
+
1
, find:
\newline
a.
f
(
x
)
+
g
(
x
)
f(x)+g(x)
f
(
x
)
+
g
(
x
)
\newline
b.
f
(
x
)
−
g
(
x
)
f(x)-g(x)
f
(
x
)
−
g
(
x
)
\newline
c.
(
f
∘
g
)
(
x
)
(f \circ g)(x)
(
f
∘
g
)
(
x
)
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Point
L
\mathrm{L}
L
is located at
−
7
-7
−
7
. Point
M
\mathrm{M}
M
is
2
2
2
greater than Point
L
\mathrm{L}
L
. Where is
M
\mathrm{M}
M
located?
\newline
M
=
□
\mathbf{M}= \square
M
=
□
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Point A is located at
−
8
-8
−
8
. Point
B
\mathrm{B}
B
is
4
4
4
greater than Point
A
\mathrm{A}
A
. Where is
B
\mathrm{B}
B
located?
\newline
B
=
□
B= \square
B
=
□
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Point
W
\mathrm{W}
W
is located at
−
6
-6
−
6
. Point
X
\mathrm{X}
X
is
8
8
8
greater than Point
W
\mathrm{W}
W
. Where is
X
\mathrm{X}
X
located?
\newline
X
=
□
\mathrm{X}=\square
X
=
□
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