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x=-b+-sqrt(b^(2))
Algebra 1
Assignment
Solve each equation with th


2n^(2)=-9n+126

-2n

-2n^(2)


-2n^(2)-9n+126=

x=b±b2 x=-b \pm \sqrt{b^{2}} \newlineAlgebra 11\newlineAssignment\newlineSolve each equation with th\newline11) 2n2=9n+126 2 n^{2}=-9 n+126 \newline2n -2 n \newline2n2 -2 n^{2} \newline2n29n+126= -2 n^{2}-9 n+126=

Full solution

Q. x=b±b2 x=-b \pm \sqrt{b^{2}} \newlineAlgebra 11\newlineAssignment\newlineSolve each equation with th\newline11) 2n2=9n+126 2 n^{2}=-9 n+126 \newline2n -2 n \newline2n2 -2 n^{2} \newline2n29n+126= -2 n^{2}-9 n+126=
  1. Move Terms to One Side: Move all terms to one side to set the equation to zero. 2n2+9n126=02n^2 + 9n - 126 = 0
  2. Factor the Equation: Factor the quadratic equation.\newline(2n14)(n+9)=0(2n - 14)(n + 9) = 0
  3. Set Equal and Solve: Set each factor equal to zero and solve for nn.2n14=02n - 14 = 0 or n+9=0n + 9 = 0
  4. Solve for nn: Solve 2n14=02n - 14 = 0.\newline2n=142n = 14\newlinen=7n = 7
  5. Final Solutions: Solve n+9=0n + 9 = 0.\newlinen=9n = -9

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