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Let’s check out your problem:
x
+
2
=
2
x
−
5
x+2=2 x-5
x
+
2
=
2
x
−
5
.
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Math Problems
Algebra 1
Solve linear equations with variables on both sides
Full solution
Q.
x
+
2
=
2
x
−
5
x+2=2 x-5
x
+
2
=
2
x
−
5
.
Move terms to sides:
Move all
x
x
x
terms to one side and constant terms to the other side.
x
+
2
−
x
=
2
x
−
5
−
x
x + 2 - x = 2x - 5 - x
x
+
2
−
x
=
2
x
−
5
−
x
2
=
x
−
5
2 = x - 5
2
=
x
−
5
Add
5
5
5
to isolate x:
Add
5
5
5
to both sides to isolate x.
\newline
2
+
5
=
x
−
5
+
5
2 + 5 = x - 5 + 5
2
+
5
=
x
−
5
+
5
\newline
7
=
x
7 = x
7
=
x
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7
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(A) No solutions
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(B) Exactly one solution
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How many solutions does the following equation have?
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9
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x
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9
(
x
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6
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9
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\newline
Choose
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answer:
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(B) Exactly one solution
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(C) Infinitely many solutions
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How many solutions does the following equation have?
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(
x
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7
)
=
−
4
x
−
2
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−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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How many solutions does the following equation have?
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(B) Exactly one solution
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17
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\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Posted 4 months ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
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9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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