Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

x(1400 x+6)+2(2x+4)
The expression shown above can be expressed as 
cx^(2)+kx+m, where 
c,k, and mare constants. What is the value of 
k ?

x(1400x+6)+2(2x+4) x(1400 x+6)+2(2 x+4) \newlineThe expression shown above can be expressed as cx2+kx+m c x^{2}+k x+m , where c,k c, k , and mare constants. What is the value of k k ?

Full solution

Q. x(1400x+6)+2(2x+4) x(1400 x+6)+2(2 x+4) \newlineThe expression shown above can be expressed as cx2+kx+m c x^{2}+k x+m , where c,k c, k , and mare constants. What is the value of k k ?
  1. Expand Expression: First, let's expand the expression x(1400x+6)+2(2x+4)x(1400x + 6) + 2(2x + 4).
    x×1400x=1400x2x \times 1400x = 1400x^2
    x×6=6xx \times 6 = 6x
    2×2x=4x2 \times 2x = 4x
    2×4=82 \times 4 = 8
    So, x(1400x+6)+2(2x+4)=1400x2+6x+4x+8x(1400x + 6) + 2(2x + 4) = 1400x^2 + 6x + 4x + 8.
  2. Combine Like Terms: Now, let's combine like terms, specifically the xx terms.6x+4x=10x6x + 4x = 10x So, the expression becomes 1400x2+10x+81400x^2 + 10x + 8.
  3. Find Value of k: We can see that the coefficient of xx is 1010. So, the value of kk is 1010.

More problems from Find the vertex of the transformed function