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Write the repeating decimal as a fraction.\newline.889889889.889889889

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Q. Write the repeating decimal as a fraction.\newline.889889889.889889889
  1. Identify repeating pattern: Let's identify the repeating pattern in the decimal. The repeating pattern is 889889. \newlinePattern followed by splitting the decimal: \newline0.889889889=0.889+0.000889+0.000000889+0.889889889\ldots = 0.889 + 0.000889 + 0.000000889 + \ldots
  2. Express in fraction form: Now, let's express each term in fraction form.\newline0.8898898890.889889889\ldots \newline= 0.889+0.000889+0.000000889+0.889 + 0.000889 + 0.000000889 + \ldots \newline= 8891000+8891000000+8891000000000+\frac{889}{1000} + \frac{889}{1000000} + \frac{889}{1000000000} + \ldots
  3. Find common ratio: The series 8891000+8891000000+8891000000000+\frac{889}{1000} + \frac{889}{1000000} + \frac{889}{1000000000} + \ldots forms a geometric series.\newlineFind the common ratio (r)(r) in the geometric series.\newlineTwo consecutive terms are 8891000\frac{889}{1000} and 8891000000\frac{889}{1000000}.\newline(8891000000)/(8891000)\left(\frac{889}{1000000}\right) / \left(\frac{889}{1000}\right) \newline=8891000000×1000889= \frac{889}{1000000} \times \frac{1000}{889} \newline=11000= \frac{1}{1000}\newlineCommon Ratio (r)(r): 11000\frac{1}{1000}
  4. Write as fraction: Write the repeating decimal as a fraction using the formula for the sum of an infinite geometric series, which is a1/(1r)a_1 / (1 - r), where a1a_1 is the first term and rr is the common ratio.\newlineSubstitute a1=889/1000a_1 = 889/1000 and r=1/1000r = 1/1000 into the formula.\newline= (889/1000)/(11/1000)(889/1000) / (1 - 1/1000)\newline= (889/1000)/(999/1000)(889/1000) / (999/1000)\newline= 889/1000×1000/999889/1000 \times 1000/999\newline= 889/999889/999

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