Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Write the expression using exponents. Enter a number in every blank. $\newline$ $13 \cdot 13 \cdot 70$ $\newline$ $13^{--}\cdot70^{--}$

View step-by-step help

View step-by-step help

Writing from expanded to exponent form

Full solution

Q. Write the expression using exponents. Enter a number in every blank.

\newline

13 \cdot 13 \cdot 70

\newline

13^{--}\cdot70^{--}

Count number occurrences: Count how many times each number appears. $13$ appears twice, and $70$ appears once. Calculation: $13 \cdot 13 = 13^2$ , $70 = 70^1$
Write expression using exponents: Write the expression using exponents. $\newline$ $13$ is multiplied by itself $2$ times, so it's written as $13^2$ . $\newline$ $70$ is not multiplied by itself but still needs an exponent, so it's written as $70^1$ .

More problems from Writing from expanded to exponent form

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 2 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 2 months ago

Question

x^2 = 4

Posted 1 month ago

Question

x^2 = 9

Posted 3 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 3 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 3 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 3 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 4 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 1 month ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 1 month ago