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Write the equation of the quadratic function given the three points on the function. Write the equation in standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c. (0,12)(0, -12), (1,9)(1, -9), (2,36)(-2, -36)

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Q. Write the equation of the quadratic function given the three points on the function. Write the equation in standard form f(x)=ax2+bx+cf(x) = ax^2 + bx + c. (0,12)(0, -12), (1,9)(1, -9), (2,36)(-2, -36)
  1. Find cc: Plug in the first point (0,12)(0, -12) into the standard form equation to find cc.f(x)=ax2+bx+cf(x) = ax^2 + bx + c12=a(0)2+b(0)+c-12 = a(0)^2 + b(0) + cc=12c = -12
  2. Relationship between aa and bb: Plug in the second point (1,9)(1, -9) into the standard form equation to find a relationship between aa and bb.
    9=a(1)2+b(1)+c-9 = a(1)^2 + b(1) + c
    9=a+b12-9 = a + b - 12
    a+b=3a + b = 3
  3. Another relationship between a and b: Plug in the third point (2,36)(-2, -36) into the standard form equation to find another relationship between a and b.\newline36=a(2)2+b(2)+c-36 = a(-2)^2 + b(-2) + c\newline36=4a2b12-36 = 4a - 2b - 12\newline4a2b=244a - 2b = -24
  4. Solve system of equations: Solve the system of equations from the second and third steps to find aa and bb.a+b=3a + b = 34a2b=244a - 2b = -24Multiply the first equation by 22 and add to the second equation.2a+2b=62a + 2b = 64a2b=244a - 2b = -246a=186a = -18a=3a = -3
  5. Find bb: Substitute a=3a = -3 into the first equation to find bb.\newline3+b=3-3 + b = 3\newlineb=6b = 6
  6. Write final equation: Write the final equation using the values of aa, bb, and cc.f(x)=ax2+bx+cf(x) = ax^2 + bx + cf(x)=3x2+6x12f(x) = -3x^2 + 6x - 12

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