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Write the equation of the parabola that passes through the points (3,0)(3,0), (2,27)(2,-27), and (1,0)(-1,0). Write your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.

Full solution

Q. Write the equation of the parabola that passes through the points (3,0)(3,0), (2,27)(2,-27), and (1,0)(-1,0). Write your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.
  1. Identify x-intercepts: Identify the x-intercepts from the given points.\newlineThe x-intercepts are the x-values of the points where the y-values are zero.\newlinex-intercepts: 33, 1-1
  2. Write equation in form: Use the xx-intercepts to write the equation in the form y=a(xp)(xq)y = a(x - p)(x - q).p=3p = 3q=1q = -1y=a(x3)(x(1))y = a(x - 3)(x - (-1))y=a(x3)(x+1)y = a(x - 3)(x + 1)
  3. Use point to find 'a': Use the point (2,27)(2,-27) to find the value of 'a'.\newliney=a(x3)(x+1)y = a(x - 3)(x + 1)\newline27=a(23)(2+1)-27 = a(2 - 3)(2 + 1)\newline27=a(1)(3)-27 = a(-1)(3)\newline27=3a-27 = -3a
  4. Solve for 'a': Solve for 'a'.\newline27=3a-27 = -3a\newlinea=273a = \frac{-27}{-3}\newlinea=9a = 9
  5. Write final equation: Write the final equation of the parabola using the value of aa and the x-intercepts.a=9a = 9p=3p = 3q=1q = -1y=a(xp)(xq)y = a(x - p)(x - q)y=9(x3)(x+1)y = 9(x - 3)(x + 1)

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