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While organizing her DVD collection, Erin put 3535 DVDs on the first rack, 5050 DVDs on the second rack, 6565 DVDs on the third rack, and 8080 DVDs on the fourth rack. What kind of sequence is this?\newlineChoices:\newline(A) arithmetic\newline(B) geometric\newline(C) both\newline(D) neither

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Q. While organizing her DVD collection, Erin put 3535 DVDs on the first rack, 5050 DVDs on the second rack, 6565 DVDs on the third rack, and 8080 DVDs on the fourth rack. What kind of sequence is this?\newlineChoices:\newline(A) arithmetic\newline(B) geometric\newline(C) both\newline(D) neither
  1. Find Differences: To determine the type of sequence, we need to look at the differences or ratios between the terms. Let's start by finding the differences between consecutive terms.\newlineFirst rack: 3535 DVDs\newlineSecond rack: 5050 DVDs\newlineThird rack: 6565 DVDs\newlineFourth rack: 8080 DVDs\newlineDifference between second and first rack: 5035=1550 - 35 = 15\newlineDifference between third and second rack: 6550=1565 - 50 = 15\newlineDifference between fourth and third rack: 8065=1580 - 65 = 15
  2. Arithmetic Sequence: Since the differences between consecutive terms are constant, this indicates that the sequence is an arithmetic sequence.
  3. Check Geometric Sequence: Now let's check if it could also be a geometric sequence by finding the ratios between consecutive terms.\newlineRatio of second to first rack: 5035\frac{50}{35}\newlineRatio of third to second rack: 6550\frac{65}{50}\newlineRatio of fourth to third rack: 8065\frac{80}{65}
  4. Calculate Ratios: Calculating the ratios:\newline50351.4286\frac{50}{35} \approx 1.4286\newline6550=1.3\frac{65}{50} = 1.3\newline80651.2308\frac{80}{65} \approx 1.2308\newlineSince the ratios are not constant, this is not a geometric sequence.
  5. Conclusion: Based on the constant differences and non-constant ratios, we can conclude that the sequence is an arithmetic sequence and not a geometric sequence.

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