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Which type of conic section is defined by the equation 
4x^(2)-16y^(2)+16 x-160 y-448=0 ?
This is an equation of

Which type of conic section is defined by the equation 4x216y2+16x160y448=0 4 x^{2}-16 y^{2}+16 x-160 y-448=0 ?\newlineThis is an equation of

Full solution

Q. Which type of conic section is defined by the equation 4x216y2+16x160y448=0 4 x^{2}-16 y^{2}+16 x-160 y-448=0 ?\newlineThis is an equation of
  1. Simplify Equation: Step 11: Simplify the equation by grouping similar terms. 4x2+16x16y2160y448=04x^2 + 16x - 16y^2 - 160y - 448 = 0
  2. Rearrange for Identification: Step 22: Rearrange the equation to make it easier to identify. 4x2+16x16y2160y=4484x^2 + 16x - 16y^2 - 160y = 448
  3. Divide and Simplify: Step 33: Divide the entire equation by 44 to simplify.x2+4x4y240y=112x^2 + 4x - 4y^2 - 40y = 112
  4. Complete the Square: Step 44: Complete the square for the xx-terms and yy-terms.(x2+4x)4(y2+10y)=112(x^2 + 4x) - 4(y^2 + 10y) = 112Adding and subtracting 44 inside the first parenthesis and 100100 inside the second parenthesis:(x2+4x+44)4(y2+10y+2525)=112(x^2 + 4x + 4 - 4) - 4(y^2 + 10y + 25 - 25) = 112(x+2)244((y+5)225)=112(x + 2)^2 - 4 - 4((y + 5)^2 - 25) = 112(x+2)24(y+5)2+100=112(x + 2)^2 - 4(y + 5)^2 + 100 = 112
  5. Further Simplification: Step 55: Simplify the equation further.\newline(x+2)24(y+5)2=12(x + 2)^2 - 4(y + 5)^2 = 12
  6. Identify Conic Section: Step 66: Identify the type of conic section.\newlineThe equation (x+2)24(y+5)2=12(x + 2)^2 - 4(y + 5)^2 = 12 is in the form of a hyperbola because it has one squared term subtracted from another squared term.

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