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Which recursive formula can be used to define this sequence for n>1n > 1?\newline12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots\newlineChoices:\newline(A) a=10aa = 10a\newline(B) a=a+a+10a = a + a + 10\newline(C) a=a+10a = a + 10\newline(D) a=116aa = \frac{11}{6}a

Full solution

Q. Which recursive formula can be used to define this sequence for n>1n > 1?\newline12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots\newlineChoices:\newline(A) a=10aa = 10a\newline(B) a=a+a+10a = a + a + 10\newline(C) a=a+10a = a + 10\newline(D) a=116aa = \frac{11}{6}a
  1. Find Pattern: We need to find a pattern in the sequence to determine the recursive formula. The given sequence is 12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots Each term increases by 1010 from the previous term.
  2. Define Recursive Formula: To express this pattern as a recursive formula, we need to define the nnth term (ana_n) based on the (n1)(n-1)th term (an1a_{n-1}). Since each term is 1010 more than the previous term, the recursive formula will be an=an1+10a_n = a_{n-1} + 10.
  3. Check Choices: Now we check the given choices to see which one matches our recursive formula. The correct choice should express that each term is 1010 more than the previous term.
  4. Incorrect Choice (A): Choice (A) a=10aa = 10a is incorrect because it implies that each term is 1010 times the previous term, which is not the case.
  5. Incorrect Choice (B): Choice (B) a=a+a+10a = a + a + 10 is incorrect because it implies that each term is double the previous term plus 1010, which is not the case.
  6. Correct Choice (C): Choice (C) a=a+10a = a + 10 is the correct choice because it matches our recursive formula, stating that each term is 1010 more than the previous term.
  7. Incorrect Choice (D): Choice (D) a=116aa = \frac{11}{6}a is incorrect because it implies that each term is a fraction of the previous term, which is not the case.

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