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Which recursive formula can be used to define this sequence for n>1n > 1?\newline12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots\newlineChoices:\newline(A) an=an1+10a_{n} = a_{n-1} + 10\newline(B) an=116an1a_{n} = \frac{11}{6}a_{n-1}\newline(C) an=an1+an1+10a_{n} = a_{n-1} + a_{n-1} + 10\newline(D) an=10an1a_{n} = 10a_{n-1}

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Q. Which recursive formula can be used to define this sequence for n>1n > 1?\newline12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots\newlineChoices:\newline(A) an=an1+10a_{n} = a_{n-1} + 10\newline(B) an=116an1a_{n} = \frac{11}{6}a_{n-1}\newline(C) an=an1+an1+10a_{n} = a_{n-1} + a_{n-1} + 10\newline(D) an=10an1a_{n} = 10a_{n-1}
  1. Sequence Type: We have the sequence: 12,22,32,42,52,62,12, 22, 32, 42, 52, 62, \ldots\newlineIs the given sequence geometric or arithmetic?\newlineThe difference between consecutive terms is the same.\newlineThe given sequence is arithmetic.
  2. Find Common Difference: Find the common difference, dd.\newlineTwo consecutive terms are 1212 and 2222.\newline2212=1022 - 12 = 10\newlineCommon difference (dd): 1010
  3. Recursive Formula: Identify the recursive formula for the given sequence.\newlineSubstitute 1010 for dd in an=an1+da_n = a_{n-1} + d.\newlineRecursive formula: an=an1+10a_n = a_{n-1} + 10

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