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Which half-reaction equation represents the reduction of an iron(II) ion?
(1) 
Fe^(2+)longrightarrowFe^(3+)+e^(-)
(3) 
Fe^(3+)+e^(-)longrightarrowFe^(2+)
(2) 
Fe^(2+)+2e^(-)longrightarrowFe
(4) 
FelongrightarrowFe^(2+)+2e^(-)
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Which half-reaction equation represents the reduction of an iron(II) ion?\newline(11) Fe2+Fe3++e \mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-} \newline(33) Fe3++eFe2+ \mathrm{Fe}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{2+} \newline(22) Fe2++2eFe \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe} \newline(44) FeFe2++2e \mathrm{Fe} \longrightarrow \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \newline11\newline22\newline33\newline44\newlineClear selection

Full solution

Q. Which half-reaction equation represents the reduction of an iron(II) ion?\newline(11) Fe2+Fe3++e \mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-} \newline(33) Fe3++eFe2+ \mathrm{Fe}^{3+}+\mathrm{e}^{-} \longrightarrow \mathrm{Fe}^{2+} \newline(22) Fe2++2eFe \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe} \newline(44) FeFe2++2e \mathrm{Fe} \longrightarrow \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \newline11\newline22\newline33\newline44\newlineClear selection
  1. Identify Reduction Process: Reduction involves the gain of electrons. Look for the equation where iron is gaining electrons.
  2. Analyzing Option (11): Option (11) shows Fe2+\text{Fe}^{2+} losing an electron to become Fe3+\text{Fe}^{3+}, which is oxidation, not reduction.
  3. Analyzing Option (22): Option (22) shows Fe2+\text{Fe}^{2+} gaining 22 electrons to become Fe\text{Fe}, which is reduction, but it's the reduction of Fe2+\text{Fe}^{2+} to Fe\text{Fe}, not to Fe3+\text{Fe}^{3+}.
  4. Analyzing Option (33): Option (33) shows Fe3+\text{Fe}^{3+} gaining an electron to become Fe2+\text{Fe}^{2+}, which is reduction and represents the reduction of an iron(III) ion to an iron(II) ion.
  5. Analyzing Option (44): Option (44) shows FeFe turning into Fe2+Fe^{2+} by losing two electrons, which is oxidation, not reduction.

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