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What's the limit of (2x+3x)\left(\frac{2x + 3}{x}\right) when xx tends to infinity?

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Q. What's the limit of (2x+3x)\left(\frac{2x + 3}{x}\right) when xx tends to infinity?
  1. Given Function Simplification: We are given the function (2x+3)/x(2x + 3)/x and we want to find the limit as xx approaches infinity. To do this, we can divide each term in the numerator by xx to simplify the expression.
  2. Divide by x: Divide each term in the numerator by x:\newline(2x+3)/x=(2x/x)+(3/x)=2+(3/x)(2x + 3)/x = (2x/x) + (3/x) = 2 + (3/x).
  3. Limit of Individual Terms: Now, we consider the limit of each term separately as xx approaches infinity: limx2=2\lim_{x \to \infty} 2 = 2, since 22 is a constant and its limit is itself. limx(3x)=0\lim_{x \to \infty} \left(\frac{3}{x}\right) = 0, because as xx becomes very large, 3x\frac{3}{x} approaches 00.
  4. Combine Limits: Combine the limits of the individual terms to find the limit of the entire expression: limx(2+(3/x))=limx2+limx(3/x)=2+0=2\lim_{x \to \infty} (2 + (3/x)) = \lim_{x \to \infty} 2 + \lim_{x \to \infty} (3/x) = 2 + 0 = 2.

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