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Find 
lim_(x rarr oo)(x+1)/(x^(2)+1).
Choose 1 answer:
(A) 1
(B) 2
(C) 0
(D) The limit is unbounded

Find limxx+1x2+1 \lim _{x \rightarrow \infty} \frac{x+1}{x^{2}+1} .\newlineChoose 11 answer:\newline(A) 11\newline(B) 22\newline(C) 00\newline(D) The limit is unbounded

Full solution

Q. Find limxx+1x2+1 \lim _{x \rightarrow \infty} \frac{x+1}{x^{2}+1} .\newlineChoose 11 answer:\newline(A) 11\newline(B) 22\newline(C) 00\newline(D) The limit is unbounded
  1. Analyze Behavior of Functions: We are asked to find the limit of the function (x+1)/(x2+1)(x+1)/(x^2+1) as xx approaches infinity. To do this, we will analyze the behavior of the numerator and the denominator separately as xx grows without bound.
  2. Degree of Polynomials: The degree of the polynomial in the numerator is 11 (since the highest power of xx is x1x^1), and the degree of the polynomial in the denominator is 22 (since the highest power of xx is x2x^2). When the degree of the denominator is higher than the degree of the numerator, the limit as xx approaches infinity is 00.
  3. Divide Numerator and Denominator: To formally show this, we can divide both the numerator and the denominator by x2x^2, the highest power of xx in the denominator. This will give us:\newlinelimx(xx2+1x2)/(1+1x2).\lim_{x \rightarrow \infty}\left(\frac{x}{x^2} + \frac{1}{x^2}\right)/\left(1 + \frac{1}{x^2}\right).
  4. Simplify Expression: Simplifying the expression inside the limit, we get: limx(1x+1x2)/(1+1x2)\lim_{x \rightarrow \infty}\left(\frac{1}{x} + \frac{1}{x^2}\right)/\left(1 + \frac{1}{x^2}\right).
  5. Apply Limit as x Approaches Infinity: As xx approaches infinity, 1x\frac{1}{x} and 1x2\frac{1}{x^2} both approach 00. Therefore, the expression simplifies to: limx(0+0)/(1+0)\lim_{x \rightarrow \infty}(0 + 0)/(1 + 0).
  6. Final Limit Calculation: The limit then becomes: limx01=0\lim_{x \rightarrow \infty}\frac{0}{1} = 0.

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