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What is the value of $n$ in the equation $-14x + 10=n(7x-5)$

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Solve linear equations

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Q. What is the value of

n

in the equation

-14x + 10=n(7x-5)

Move terms with $x$ : Now, we need to get all the terms with $x$ on one side and the constant terms on the other side. $\newline$ Let's move $7nx$ to the left by subtracting $7nx$ from both sides. $\newline$ $-14x - 7nx + 10 = -5n$ .
Combine like terms: Combine like terms on the left side. $\newline$ $-14x - 7nx = -(14 + 7n)x.$ $\newline$ So, $-(14 + 7n)x + 10 = -5n.$
Isolate $n$ terms: Now, we need to isolate the $n$ terms. Let's move $10$ to the right side by subtracting $10$ from both sides. $- (14 + 7n)x = -5n - 10$ .
Equate coefficients: Since there are no $x$ terms on the right side, we can equate the coefficients of $x$ on both sides. $\newline$ This means $-(14 + 7n) = 0$ because there's no $x$ term on the right side.

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