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What is the total number of different 8-letter arrangements that can be formed using the letters in the word VEHEMENT?
Answer:

What is the total number of different 88-letter arrangements that can be formed using the letters in the word VEHEMENT?\newlineAnswer:

Full solution

Q. What is the total number of different 88-letter arrangements that can be formed using the letters in the word VEHEMENT?\newlineAnswer:
  1. Count Letters: Determine the number of times each letter appears in the word VEHEMENT. VV appears once, EE appears three times, HH appears once, MM appears once, NN appears once, and TT appears once.
  2. Total Arrangements: Calculate the total number of arrangements without considering the repetition of letters.\newlineSince the word VEHEMENT has 88 letters, if all letters were unique, the number of different arrangements would be 88 factorial (8!8!).\newline8!=8×7×6×5×4×3×2×18! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1
  3. Consider Repetition of E: Calculate the number of arrangements considering the repetition of the letter E. Since the letter E is repeated 33 times, we need to divide the total number of arrangements by the factorial of the number of times E is repeated to avoid overcounting. So we divide by 3!3! (which is the factorial of 33). 3!=3×2×13! = 3 \times 2 \times 1
  4. Calculate Permutations: Perform the actual calculation using the formula for permutations of a multiset.\newlineThe number of different arrangements (permutations) is given by:\newlineTotal arrangements = 8!3!\frac{8!}{3!}\newlineNow, calculate 8!8! and 3!3!:\newline8!=8×7×6×5×4×3×2×1=40,3208! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40,320\newline3!=3×2×1=63! = 3 \times 2 \times 1 = 6
  5. Final Answer: Divide the total number of unique arrangements by the number of repeated arrangements to get the final answer.\newlineTotal arrangements = 8!3!=40,3206=6,720\frac{8!}{3!} = \frac{40,320}{6} = 6,720

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